Đề thi minh họa môn Toán THPTQG của BGD năm 2019

A. \(8a^3\)

B. \(2a^3\)

C. \(a^3\)

D. \(6a^3\)

A. 1

B. 2

C. 0

D. 5

A. \(\left( {1;\,2;\,3} \right)\)

B. \(\left( { - 1;\, - 2;\,3} \right)\)

C. \(\left( {3;\,5;\,1} \right)\)

D. \(\left( {3;\,4;\,1} \right)\)

A. \((0;1)\)

B. \(\left( { - \infty ;1} \right)\)

C. \(\left( { - 1;1} \right)\)

D. \(\left( { - 1;0} \right)\)

A. \(2\log a + \log b\)

B. \(\log a + 2\log b\)

C. \(2\left( {\log a + \log b} \right)\)

D. \(\log a + \frac{1}{2}\log b\)

A. \(-3\)

B. \(12\)

C. \(-8\)

D. \(1\)

A. \(\frac{{4\pi {a^3}}}{3}\)

B. \(4\pi {a^3}\)

C. \(\frac{{\pi {a^3}}}{3}\)

D. \(2\pi {a^3}\)

A. \({0}\)

B. \({0;1}\)

C. \({-1;0}\)

D. \({1}\)

A. \(5\)

B. \(x + y + z = 0\)

C. \(y=0\)

D. \(x=0\)

A. \({{\rm{e}}^x} + {x^2} + C\)

B. \({{\rm{e}}^x} + \frac{1}{2}{x^2} + C\)

C. \(\frac{1}{{x + 1}}{{\rm{e}}^x} + \frac{1}{2}{x^2} + C\)

D. \({{\rm{e}}^x} + 1 + C\)

A. \(Q\left( {2; - 1;2} \right)\)

B. \(M\left( { - 1; - 2; - 3} \right)\)

C. \(P\left( {1;2;3} \right)\)

D. \(N\left( { - 2;1; - 2} \right)\)

A. \(C_n^k = \frac{{n!}}{{k!\left( {n - k} \right)!}}\)

B. \(C_n^k = \frac{{n!}}{{k!}}\)

C. \(C_n^k = \frac{{n!}}{{\left( {n - k} \right)!}}\)

D. \(C_n^k = \frac{{k!\left( {n - k} \right)!}}{{n!}}\)

A. 22

B. 17

C. 12

D. 250

A. N

B. P

C. M

D. Q

A. \(y = \frac{{2x - 1}}{{x - 1}}\)

B. \(y = \frac{{x + 1}}{{x - 1}}\)

C. \(y = {x^4} + {x^2} + 1\)

D. \(y = {x^3} - 3x - 1\)

A. 0

B. 1

C. 4

D. 5

A. 3

B. 2

C. 5

D. 1

A. \(a = 0,\,\,b = 2\)

B. \(a = \frac{1}{2},\,\,b = 1\)

C. \(a = 0,\,\,b = 1\)

D. \(a = 1,\,\,b = 2\)

A. \({\left( {x + 1} \right)^2} + {\left( {y + 1} \right)^2} + {\left( {z + 1} \right)^2} = 29\)

B. \({\left( {x - 1} \right)^2} + {\left( {y - 1} \right)^2} + {\left( {z - 1} \right)^2} = 5\)

C. \({\left( {x - 1} \right)^2} + {\left( {y - 1} \right)^2} + {\left( {z - 1} \right)^2} = 25\)

D. \({\left( {x + 1} \right)^2} + {\left( {y + 1} \right)^2} + {\left( {z + 1} \right)^2} = 5\)

A. \(\frac{{3a}}{4}\)

B. \(\frac{3}{{4a}}\)

C. \(\frac{4}{{3a}}\)

D. \(\frac{{4a}}{3}\)

A. \(2\sqrt 5 \)

B. \(\sqrt 5 \)

C. \(3\)

D. \(10\)

A. \(\frac{8}{3}\)

B. \(\frac{7}{3}\)

C. \(3\)

D. \(\frac{4}{3}\)

A. \(\left( { - \infty ; - 1} \right)\)

B. \(\left( {3; + \infty } \right)\)

C. \(\left( { - 1;3} \right)\)

D. \(\left( { - \infty ; - 1} \right) \cup \left( {3; + \infty } \right)\)

A. \(\int\limits_{ - 1}^2 {\left( {2{x^2} - 2x - 4} \right)\,{\rm{d}}x} \)

B. \(\int\limits_{ - 1}^2 {\left( { - 2x + 2} \right)\,{\rm{d}}x} \)

C. \(\int\limits_{ - 1}^2 {\left( {2x - 2} \right)\,{\rm{d}}x} \)

D. \(\int\limits_{ - 1}^2 {\left( { - 2{x^2} + 2x + 4} \right)\,{\rm{d}}x} \)

A. \(\frac{{\sqrt 3 \pi {a^3}}}{3}\)

B. \(\frac{{\sqrt 3 \pi {a^3}}}{2}\)

C. \(\frac{{2\pi {a^3}}}{3}\)

D. \(\frac{{\pi {a^3}}}{3}\)

A. 4

B. 1

C. 3

D. 2

A. \(\frac{{4\sqrt 2 {a^3}}}{3}\)

B. \(\frac{{8{a^3}}}{3}\)

C. \(\frac{{8\sqrt 2 {a^3}}}{3}\)

D. \(\frac{{2\sqrt 2 {a^3}}}{3}\)

A. \(f'\left( x \right) = \frac{{\ln 2}}{{{x^2} - 2x}}\)

B. \(f'\left( x \right) = \frac{1}{{\left( {{x^2} - 2x} \right)\ln 2}}\)

C. \(f'\left( x \right) = \frac{{\left( {2x - 2} \right)\ln 2}}{{{x^2} - 2x}}\)

D. \(f'\left( x \right) = \frac{{2x - 2}}{{\left( {{x^2} - 2x} \right)\ln 2}}\)

A. 4

B. 3

C. 2

D. 1

A. \(30^0\)

B. \(60^0\)

C. \(45^0\)

D. \(90^0\)

A. 2

B. 1

C. 7

D. 3

A. \(24{\rm{ }}\left( {{\rm{c}}{{\rm{m}}^3}} \right)\)

B. \(15{\rm{ }}\left( {{\rm{c}}{{\rm{m}}^{\rm{3}}}} \right)\)

C. \(20{\rm{ }}\left( {{\rm{c}}{{\rm{m}}^3}} \right)\)

D. \(10{\rm{ }}\left( {{\rm{c}}{{\rm{m}}^3}} \right)\)

A. \(2{x^2}\ln x + 3{x^2}\)

B. \(2{x^2}\ln x + {x^2}\)

C. \(2{x^2}\ln x + 3{x^2} + C\)

D. \(2{x^2}\ln x + {x^2} + C\)

A. \(\frac{{a\sqrt {21} }}{7}\)

B. \(\frac{{a\sqrt {15} }}{7}\)

C. \(\frac{{a\sqrt {21} }}{3}\)

D. \(\frac{{a\sqrt {15} }}{3}\)

A. \(\frac{{x + 1}}{{ - 1}} = \frac{{y + 1}}{{ - 4}} = \frac{{z + 1}}{5}\)

B. \(\frac{{x - 1}}{3} = \frac{{y - 1}}{{ - 2}} = \frac{{z - 1}}{{ - 1}}\)

C. \(\frac{{x - 1}}{1} = \frac{{y - 1}}{4} = \frac{{z - 1}}{{ - 5}}\)

D. \(\frac{{x - 1}}{1} = \frac{{y + 4}}{1} = \frac{{z + 5}}{1}\)

A. \(\left( { - \infty ;\,0} \right]\)

B. \(\left[ { - \frac{3}{4};\, + \infty } \right)\)

C. \(\left( { - \infty ;\, - \frac{3}{4}} \right]\)

D. \(\left[ {0;\, + \infty } \right)\)

A. \(\left( {1; - 1} \right)\)

B. \((1;1)\)

C. \((-1;1)\)

D. \((-1;-1)\)

A. \(-2\)

B. \(-1\)

C. \(2\)

D. \(1\)

A. \(m \ge f\left( 1 \right) - {\rm{e}}\)

B. \(m > f\left( { - 1} \right) - \frac{1}{{\rm{e}}}\)

C. \(m \ge f\left( { - 1} \right) - \frac{1}{{\rm{e}}}\)

D. \(m > f\left( 1 \right) - {\rm{e}}\)

A. \(\frac{2}{5}\)

B. \(\frac{1}{{20}}\)

C. \(\frac{3}{5}\)

D. \(\frac{1}{{10}}\)

A. 135

B. 105

C. 108

D. 145

A. 4

B. 3

C. 1

D. 2

A. \(\left[ { - 1;3} \right)\)

B. \(\left( { - 1;1} \right)\)

C. \(\left( { - 1;3} \right)\)

D. \(\left[ { - 1;1} \right)\)

A. 2,22 triệu đồng 

B. 3,03 triệu đồng 

C. 2,25 triệu đồng 

D. 2,20 triệu đồng 

A. \(\left\{ \begin{array}{l}
x = 2 + 9t\\
y = 1 + 9t\\
z = 3 + 8t
\end{array} \right.\)

B. \(\left\{ \begin{array}{l}
x = 2 - 5t\\
y = 1 + 3t\\
z = 3
\end{array} \right.\)

C. \(\left\{ \begin{array}{l}
x = 2 + t\\
y = 1 - t\\
z = 3
\end{array} \right.\)

D. \(\left\{ \begin{array}{l}
x = 2 + 4t\\
y = 1 + 3t\\
z = 3 - 3t
\end{array} \right.\)

A. 7.322.000 đồng 

B. 7.213.000 đồng 

C. 5.526.000 đồng 

D. 5.782.000 đồng 

A. \(1\)

B. \(\frac{1}{3}\)

C. \(\frac{1}{2}\)

D. \(\frac{2}{3}\)

A. \(\left( {1; + \infty } \right)\)

B. \(\left( { - \infty ; - 1} \right)\)

C. \(\left( { - 1;0} \right)\)

D. \(\left( {0;2} \right)\)

A. \( - \frac{3}{2}\)

B. \(1\)

C. \( - \frac{1}{2}\)

D. \( \frac{1}{2}\)

A. 4

B. 3

C. 1

D. 2