Đề thi HK2 môn Toán lớp 12 năm 2018 - 2019 Trường THPT M.V.LÔMÔNÔXỐP - Hà Nội

A. 1

B. 3

C. 0

D. - 1

A. 10

B. 12

C. 3

D. 4

A. - 2019

B. 2019

C. - 2019i

D. 2019i

A. \(V = 9\pi \)

B. \(V = 12\pi \)

C. \(V = 25\pi \)

D. \(V = 16\pi \)

A. \(\int {{2^x}dx = \frac{{{2^{x + 1}}}}{{x + 1}} + C} \)

B. \(\int {\sin xdx =  - \cos x + C} \)

C. \(\int {dx = x + C} \)

D. \(\int {\frac{1}{x}dx = \ln \left| x \right| + C} \)

A. \(\left| {\overrightarrow {u\,} } \right| = \sqrt {{x^2} + {y^2} + {z^2}} \)

B. \(\overrightarrow {u\,} .\overrightarrow {v\,}  = \left( {x.x';y.y';z.z'} \right)\)

C. \(\overrightarrow {u\,}  + \overrightarrow {v\,}  = \left( {x + x';y + y';z + z'} \right)\)

D. \(\overrightarrow {u\,}  - \overrightarrow {v\,}  = \left( {x - x';y - y';z - z'} \right)\)

A. \(\frac{{x - 2}}{1} = \frac{y}{3} = \frac{{z + 3}}{5}\)

B. \(\frac{{x - 1}}{{ - 1}} = \frac{{y + 3}}{3} = \frac{{z - 2}}{5}\)

C. \(\frac{{x - 2}}{1} = \frac{y}{{ - 3}} = \frac{{z + 3}}{5}\)

D. \(\frac{{x - 1}}{1} = \frac{{y + 3}}{3} = \frac{{z - 2}}{{ - 5}}\)

A. \(R = \sqrt 6 \)

B. R = 6

C. R = 36²

D. R = 36

A. \(x - 2y - z + 5 = 0\)

B. \(x - 2y - z - 5 = 0\)

C. \(2x - y - z - 5 = 0\)

D. \(2x - y - z + 5 = 0\)

A. 15

B. 5

C. - 5

D. 2

A. m = - 1

B. m = 1

C. m = 0

D. m = 2

A. \({a^2} + {b^2} = 0\)

B. \({a^2} + {b^2} = 5\)

C. \({a^2} + {b^2} = 2\)

D. \({a^2} + {b^2} = 1\)

A. \(S = \frac{{124}}{3}\)

B. \(S = \frac{{3124}}{5}\)

C. \(S = \frac{{124}}{3}\pi \)

D. \(S = \frac{{3124}}{5}\pi \)

A. \(A - B + C = 5\)

B. \(A - B + C = -3\)

C. \(A - B + C = -5\)

D. \(A - B + C = 3\)

A. \(\int {\sin 3xdx =  - \frac{1}{3}\cos 3x + C} \)

B. \(\int {\sin 3xdx = \frac{1}{3}\cos 3x + C} \)

C. \(\int {\sin 3xdx =  - 3\cos 3x + C} \)

D. \(\int {\sin 3xdx = 3\cos 3x + C} \)

A. \(\overrightarrow {n\,}  = \left( { - 2;2; - 10} \right)\)

B. \(\overrightarrow {n\,}  = \left( {1; - 2;2} \right)\)

C. \(\overrightarrow {n\,}  = \left( {1;2;2} \right)\)

D. \(\overrightarrow {n\,}  = \left( {2; - 2;1} \right)\)

A. \(I\left( { - 2;4;4} \right)\)

B. \(I\left( {1; - 2; - 2} \right)\)

C. \(I\left( { - 1;2;2} \right)\)

D. \(I\left( {2; - 4; - 4} \right)\)

A. - 21

B. - 4

C. 4

D. 21

A. \(S = 32 - 33i\)

B. \(S = 33 - 32i\)

C. \(S = 32 + 33i\)

D. \(S = 33 + 32i\)

A. \(F(x) = \left( {\frac{{{x^2}}}{2} + x} \right)\ln x + \frac{{{x^2}}}{4} + x - \frac{1}{2}\)

B. \(F(x) = \left( {\frac{{{x^2}}}{2} + x} \right)\ln x - \frac{{{x^2}}}{4} - x + 2\)

C. \(F(x) = \ln x - \frac{{{x^2}}}{2} - x + \frac{9}{4}\)

D. \(F(x) = \ln x + \frac{{{x^2}}}{2} + x - \frac{3}{4}\)

A. (5;- 1)

B. (5;1)

C. (- 1;5)

D. (1;5)

A. S = 10

B. S = - 10

C. S = - 4

D. S = 4

A. \(\frac{{\sqrt {205} }}{{10}}\)

B. \(\frac{{\sqrt {210} }}{{10}}\)

C. \(\frac{{\sqrt {210} }}{{5}}\)

D. \(\frac{{\sqrt {205} }}{5}\)

A. \(f(x) = 6x - \frac{1}{{2\sqrt x }}\)

B. \(f(x) = {x^3} - \frac{1}{{2\sqrt x }}\)

C. \(f(x) = 6x + \frac{1}{{2\sqrt x }}\)

D. \(f(x) = {x^3} + \frac{1}{{2\sqrt x }}\)

A. \(\frac{{13}}{{10}}\)

B. \(\frac{{ - 11}}{{29}}\)

C. \(\frac{{ - 11}}{{10}}\)

D. \(\frac{{ 13}}{{29}}\)

A. \(I\left( {0;\sqrt 5 } \right)\)

B. I(2;0)

C. I(- 2;0)

D. \(I\left( {0;-\sqrt 5 } \right)\)

A. \(\overrightarrow {u\,}  = \left( {1; - 3;2} \right)\)

B. \(\overrightarrow {u\,}  = \left( {2; - 1;3} \right)\)

C. \(\overrightarrow {u\,}  = \left( {2;1;3} \right)\)

D. \(\overrightarrow {u\,}  = \left( {1;3;2} \right)\)

A. \(\left| z \right| = \sqrt {34} \)

B. \(\left| z \right| = \sqrt {35} \)

C. \(\left| z \right| = \sqrt {37} \)

D. \(\left| z \right| = \sqrt {31} \)

A. Nếu \(\Delta =0\) thì phương trình có nghiệm kép.

B. Nếu \(\Delta <0\) thì phương trình vô nghiệm.

C. Nếu \(\Delta  \ne 0\) thì phương trình có hai nghiệm.

D. Nếu phương trình có hai nghiệm \(z_1, z_2\) thì \({z_1} + {z_2} =  - \frac{b}{a}\).

A. \(S = \frac{{17}}{6}\)

B. \(S = \frac{{53}}{6}\)

C. \(S = \frac{{1}}{6}\)

D. \(S = \frac{{37}}{3}\)

A. \(\int\limits_a^b {f(x)dx = F(b) - F(a)} \)

B. \(\int\limits_a^b {f(x)dx = F(b) + F(a)} \)

C. \(\int\limits_a^b {f(x)dx = F(b).F(a)} \)

D. \(\int\limits_a^b {f(x)dx = F(a) - F(b)} \)

A. \(V = \pi \int\limits_2^5 {{e^{ - 2x}}dx} \)

B. \(V = \int\limits_2^5 {{e^{ - 2x}}dx} \)

C. \(V = \int\limits_2^5 {{e^{ - x}}dx} \)

D. \(V = \pi \int\limits_2^5 {{e^{ - x}}dx} \)

A. \(\int {\frac{{{t^2} + 3}}{t}dt} \)

B. \(\int {2\left( {{t^2} + 3} \right)dt} \)

C. \(\int {2t\left( {{t^2} + 3} \right)dt} \)

D. \(\int {\frac{{{t^2} + 3}}{2}dt} \)

A. \(d\left( {I;(P)} \right) < R\)

B. \(d\left( {I;(P)} \right) > R\)

C. \(d\left( {I;(P)} \right) = R\)

D. \(d\left( {I;(P)} \right) = 0\)

A. \(\left| w \right| = 25\)

B. \(\left| w \right| = 3\sqrt 2 \)

C. \(\left| w \right| = 5\)

D. \(\left| w \right| = 18\)

A. \(\left| z \right| = 2\)

B. \(\left| z \right| = 1\)

C. \(\left| z \right| = \sqrt 2 \)

D. \(\left| z \right| = 2\sqrt 2 \)

A. 54 m

B. 90 m

C. 72 m

D. 40 m

A. \(V = \frac{9}{2}\)

B. \(V = \frac{9}{2}\pi \)

C. \(V = \frac{{81}}{{10}}\)

D. \(V = \frac{{81}}{{10}}\pi \)

A. \(I = \frac{4}{{{e^2}}}\)

B. \(I = \frac{16}{{{e^3}}}\)

C. \(I = \frac{6}{{{e^2}}}\)

D. \(I = \frac{20}{{{e^3}}}\)

A. \(d = \frac{{6\sqrt {11} }}{{11}}\)

B. \(d = \frac{{5\sqrt {11} }}{{11}}\)

C. \(d = \frac{{3\sqrt {11} }}{{11}}\)

D. \(d = \frac{{4\sqrt {11} }}{{11}}\)

A. \(\left| {\bar z} \right| = 5\)

B. \(\left| {\bar z} \right| = 1\)

C. \(\left| {\bar z} \right| = 25\)

D. \(\left| {\bar z} \right| = 4\)

A. Đường tròn \({\left( {x - 1} \right)^2} + {\left( {y + 2} \right)^2} = 13\)

B. Đường thẳng \(x + 5y - 4 = 0\)

C. Đường tròn \({\left( {x - 3} \right)^2} + {\left( {y + 3} \right)^2} = 5\)

D. Đường thẳng \(x + y - 4 = 0\)

A. \(\frac{{x + 1}}{2} = \frac{{y - 2}}{1} = \frac{{z + 1}}{{ - 1}}\)

B. \(\frac{{x - 1}}{2} = \frac{{y + 2}}{1} = \frac{{z - 1}}{{ - 1}}\)

C. \(\frac{{x + 2}}{1} = \frac{{y + 1}}{{ - 2}} = \frac{{z - 1}}{1}\)

D. \(\frac{{x - 2}}{1} = \frac{{y - 1}}{{ - 2}} = \frac{{z + 1}}{1}\)

A. \({z_4} = 3 + 5i\)

B. \({z_4} = 7 - i\)

C. \({z_4} = 5 - 5i\)

D. \({z_4} =  - 1 - i\)

A. \(45^0\)

B. \(60^0\)

C. \(30^0\)

D. \(90^0\)

A. \(\left\{ \begin{array}{l}
x = 2 + 3t\\
y = 1 - t\\
z =  - 2
\end{array} \right.\)

B. \(\left\{ \begin{array}{l}
x = 3 + 2t\\
y =  - 1 + t\\
z =  - 2t
\end{array} \right.\)

C. \(\left\{ \begin{array}{l}
x =  - 3 + 2t\\
y = 1 + t\\
z =  - 2t
\end{array} \right.\)

D. \(\left\{ \begin{array}{l}
x = 3t\\
y = 1 - t\\
z =  - 2 + t
\end{array} \right.\)

A. \(abc=2\)

B. \(abc=4\)

C. \(abc=1\)

D. \(abc=0\)

A. \(\int {\frac{{{{\ln }^2}x}}{x}dx = 2\ln x + C} \)

B. \(\int {\frac{{{{\ln }^2}x}}{x}dx = 3{{\ln }^3}x + C} \)

C. \(\int {\frac{{{{\ln }^2}x}}{x}dx = \ln x + C} \)

D. \(\int {\frac{{{{\ln }^2}x}}{x}dx = \frac{{{{\ln }^3}x}}{3} + C} \)

A. - 5

B. - 5- 5i

C. 5+5i

D. - 5i

A. \(I( - 2;2; - 4)\)

B. \(I(1;0;1)\)

C. \(I( - 1;1; - 2)\)

D. \(I(2;0;2)\)