Đề thi HK2 môn Toán 12 Trường THPT An Phước - Ninh Thuận năm học 2017 - 2018

A. \(\int {{{10}^x}{\rm{d}}x}  = \frac{{{{10}^x}}}{{\ln 10}} + C.\)

B. \(\int {{{10}^x}{\rm{d}}x}  = {10^x}\ln 10 + C.\)

C. \(\int {{{10}^x}{\rm{d}}x}  = {10^{x + 1}} + C.\)

D. \(\int {{{10}^x}{\rm{d}}x}  = \frac{{{{10}^{x + 1}}}}{{x + 1}} + C.\)

A. \(\int {\frac{1}{{{x^2}}}} dx = \ln {x^2} + C\,.\,\)

B. \(\int {c{\rm{os}}x} dx = {\mathop{\rm s}\nolimits} {\rm{in}}x + C.\)

C. \(\int {\frac{1}{{{{\sin }^2}x}}} dx = \cot x + C.\)

D. \(\int {{e^{2x}}} dx = 2{e^x} + C\,.\,\)

A. \(\int {\left( {{e^x} + 2\sin x} \right){\rm{d}}x}  = {e^x} - {\cos ^2}x + C.\)

B. \(\int {\left( {{e^x} + 2\sin x} \right){\rm{d}}x}  = {e^x} + {\sin ^2}x + C.\)

C. \(\int {\left( {{e^x} + 2\sin x} \right){\rm{d}}x}  = {e^x} - 2\cos x + C.\)

D. \(\int {\left( {{e^x} + 2\sin x} \right){\rm{d}}x}  = {e^x} + 2\cos x + C.\)

A. \(\int {f\left( x \right)dx = } \frac{{{x^3}}}{3} + \frac{{{x^2}}}{2} - 2 + C.\)

B. \(\int {f\left( x \right)dx = } \frac{{{x^3}}}{3} + \frac{{{x^2}}}{2} + C.\)

C. \(\int {f\left( x \right)dx = } 2x + 1 + C.\)

D. \(\int {f\left( x \right)dx = } \frac{{{x^3}}}{3} + \frac{{{x^2}}}{2} - 2x + C.\)

A. \(\int {x{{({x^2} + 7)}^{15}}{\rm{d}}} x = \frac{1}{2}{\left( {{x^2} + 7} \right)^{16}} + C\)

B. \(\int {x{{({x^2} + 7)}^{15}}{\rm{d}}} x = \frac{1}{{32}}{\left( {{x^2} + 7} \right)^{16}} + C\)

C. \(\int {x{{({x^2} + 7)}^{15}}{\rm{d}}} x =  - \frac{1}{{32}}{\left( {{x^2} + 7} \right)^{16}} + C\)

D. \(\int {x{{({x^2} + 7)}^{15}}{\rm{d}}} x = \frac{1}{{16}}{\left( {{x^2} + 7} \right)^{16}} + C\)

A. \(\int {f'} \left( x \right){e^{2x}}dx = 2{x^2} - 2x + C\)

B. \(\int {f'} \left( x \right){e^{2x}}dx =  - {x^2} + 2x + C\)

C. \(\int {f'} \left( x \right){e^{2x}}dx =  - 2{x^2} + 2x + C\)

D. \(\int {f'} \left( x \right){e^{2x}}dx =  - {x^2} + x + C\)

A. 4aln4

B. 6aln2

C. 3aln2

D. 2aln4

A. \(I = \frac{{17}}{2}\)

B. \(I = \frac{{7}}{2}\)

C. \(I = \frac{{5}}{2}\)

D. \(I = \frac{{11}}{2}\)

A. (4; 6)

B. (8; 10)

C. (2; 4)

D. (6; 8)

A. I = 8

B. I = 32

C. I = 4

D. I = 16

A. \(\int\limits_1^2 {\sqrt u {\rm{d}}u} \)

B. \(I = \frac{2}{3}\sqrt {27} \)

C. \(I = \int\limits_0^3 {\sqrt u {\rm{d}}u} \)

D. \(I = \frac{2}{3}{3^{\frac{3}{2}}}\)

A. \(I = 2\pi  + 1\)

B. \(I = 2\pi  + 2\)

C. \(I = 2\pi \)

D. \(I =  - 2\pi \)

A. I = 57

B. I = 67

C. I = 37

D. I = 47

A. \(S = \frac{7}{2}\)

B. S = 4

C. \(S = \frac{3}{2}\)

D. \(S = \frac{5}{2}\)

A. \(S = \int\limits_{ - 3}^0 {f(x)dx}  - \int\limits_0^4 {f(x)dx} \)

B. \(S = \int\limits_{ - 3}^0 {f(x)dx}  + \int\limits_0^4 {f(x)dx} \)

C. \(S = \int\limits_0^{ - 3} {f(x)dx}  + \int\limits_0^4 {f(x)dx} \)

D. \(S = \int\limits_{ - 3}^4 {f(x)dx} \)

A. \({\rm{S}} = 1 + \ln 3\)

B. \({\rm{S}} = 1 - \frac{1}{2}\ln 3\)

C. \({\rm{S}} = \frac{1}{2}\ln 3\)

D. \({\rm{S}} = \frac{1}{2} + \ln 3\)

A. \(V = \frac{{16\pi }}{{15}}\)

B. \(V = \frac{{16}}{{15}}\)

C. \(V = \frac{{4\pi }}{3}\)

D. \(V = \frac{4}{3}\)

A. \(V = \frac{9}{{15}}\)

B. \(V = \frac{{8\pi }}{{15}}\)

C. \(V = \frac{8}{{15}}\)

D. \(V = \frac{{9\pi }}{{15}}\)

A. \(S = 2\pi  + \frac{1}{3}\)

B. \(S = 2\pi  - \frac{2}{3}\)

C. \(S = 2\pi  - \frac{4}{3}\)

D. \(S = 2\pi  + \frac{4}{3}\)

A. M(6; 17)

B. M(17; 6)

C. M(-17; -6)

D. M(-6; -17)

A. \(\left| z \right| = \frac{{\sqrt {26} }}{3}\)

B. \(\left| z \right| = 3\sqrt {26} \)

C. \(\left| z \right| = 2\sqrt {26} \)

D. \(\left| z \right| = \frac{{\sqrt {26} }}{2}\)

A. P = 1+ i

B. P = 1- i

C. P = -1+ i

D. P = -1 - i

A. P = 3

B. P = 10

C. P = 7

D. P = 5

A. \(P = 2\sqrt 5 \)

B.  P = 20

C. P = 10

D. \(P = \sqrt 5 \)

A. \({z^2} + 4z + 13 = 0\)

B. \({z^2} - 4z + 12 = 0\)

C. \({z^2} + 4z + 12 = 0\)

D. \({z^2} - 4z + 13 = 0\)

A. \(I\left( {\frac{3}{2};3; - \frac{1}{2}} \right)\)

B. \(I\left( {\frac{3}{2};3;\frac{1}{2}} \right)\)

C. \(I\left( {\frac{3}{2};2; - \frac{1}{2}} \right)\)

D. \(I\left( {3;6; - 1} \right)\)

A. \(AB = 2\sqrt 3 \)

B. \(AB = \sqrt {14} \)

C. \(AB = \sqrt {13} \)

D. \(AB = \sqrt {6} \)

A. m = -4

B. m = 2

C. m = 1

D. m = 0

A. \({\left( {x + 1} \right)^2} + {y^2} + {z^2} = 4\)

B. \({\left( {x - 1} \right)^2} + {y^2} + {z^2} = 2\)

C. \({\left( {x + 1} \right)^2} + {y^2} + {z^2} = 2\)

D. \({\left( {x - 1} \right)^2} + {y^2} + {z^2} = 4\)

A. I (1; 2; -3) và R = 4

B. I (-1; -2; 3) và R = 4

C. I (1; 2; -3) và R = 16

D. I (-1; -2; 3) và R = 16

A. \(x - 2y - 3z + 6 = 0.\)

B. \(x - 2y + 3z - 12 = 0.\)

C. \(x - 2y - 3z - 6 = 0.\)

D. \(x - 2y + 3z + 12 = 0.\)

A. \(\overrightarrow n  = \left( {3; - 5; - 2} \right)\)

B. \(\overrightarrow n  = \left( {-4; 5; - 2} \right)\)

C. \(\overrightarrow n  = \left( {3; - 4; 5} \right)\)

D. \(\overrightarrow n  = \left( {3; - 4; 2} \right)\)

A. \(M\left( { - 2;\,1;\, - 8} \right)\)

B. \(N\left( {4;\,2;\,1} \right)\)

C. \(P\left( {3;\,1;\,3} \right)\)

D. \(Q\left( {1;\,2;\, - 5} \right)\)

A. P(0;0; - 5)

B. N( - 5;0;0).

C. Q(2; - 1;5).

D. M(1;1;6).

A. \(d = \frac{5}{{\sqrt {29} }}.\)

B. \(d = \frac{5}{{29}}.\)

C. \(d = \frac{5}{9}.\)

D. \(d = \frac{{\sqrt 5 }}{3}.\)

A. \(\vec a = ( - 1;0; - 2)\)

B. \(\vec b = ( - 1;0;2)\)

C. \(\vec c = (1;2;2)\)

D. \(\vec d = ( - 1;1;2)\)

A. \(\left\{ \begin{array}{l}
x =  - 2 + 2t\\
y =  - 3t\\
z = 1 + t
\end{array} \right..\)

B. \(\left\{ \begin{array}{l}
x =  - 2 + 4t\\
y =  - 6t\\
z = 1 + 2t
\end{array} \right..\)

C. \(\left\{ \begin{array}{l}
x = 4 + 2t\\
y =  - 3t\\
z = 2 + t
\end{array} \right..\)

D. \(\left\{ \begin{array}{l}
x = 2 + 2t\\
y =  - 3t\\
z =  - 1 + t
\end{array} \right..\)

A. \(M\left( {2;2;2} \right).\)

B. \(M\left( {2;2;4} \right).\)

C. \(M\left( {2;3;4} \right).\)

D. \(M\left( {2;2;10} \right).\)

A. \(Q\left( { - 2; - 4;7} \right)\)

B. \(P\left( {7;2;1} \right)\)

C. \(M\left( {1; - 2;3} \right)\)

D. \(N\left( {4;0; - 1} \right)\)

A. \(\left\{ \begin{array}{l}
x = 1 + 3t\\
y = 2 - 4t\\
z = 3 - 7t
\end{array} \right.\)

B. \(\left\{ \begin{array}{l}
x =  - 1 + 8t\\
y =  - 2 + 6t\\
z =  - 3 - 14t
\end{array} \right.\)

C. \(\left\{ \begin{array}{l}
x = 1 + 4t\\
y = 2 + 3t\\
z = 3 - 7t
\end{array} \right.\)

D. \(\left\{ \begin{array}{l}
x =  - 1 + 4t\\
y =  - 2 + 3t\\
z =  - 3 - 7t
\end{array} \right.\)