Một số bài toán về viết phương trình đường thẳng có lời giải chi tiết

A (-1;-3) 

B (-1;2) 

C (2;1)  

D (0;1) 

A \(\frac{{x + 2}}{1} = \frac{{y - 1}}{0}\)

B \(\frac{{x - 2}}{2} = \frac{{y + 1}}{{ - 1}}\)

C \(\frac{{x - 2}}{{ - 1}} = \frac{{y + 1}}{2}\)

D \(\frac{{x + 2}}{0} = \frac{{y - 1}}{1}\)

A Vectơ chỉ phương là  \(\left( {4;\,\,3} \right)\)             

B Vectơ pháp tuyến \(\overrightarrow n  = ( - 3; + 4)\)

C (d) qua \(M\left( {3;\,\,0} \right)\)                                

D (d)  qua \(N\left( { - \frac{1}{3};\,\,0} \right)\)

A  \(\left( { - 2;\,\,\frac{1}{3}} \right)\) 

B \(\left( { - 1;\,\,\frac{1}{3}} \right)\)

C \(\left( {1; - \frac{1}{3}} \right)\)

D \(\left( {1;\,\,\frac{1}{3}} \right)\) 

A \(\frac{{x + 2}}{5} = \frac{{y - 3}}{{ - 1}}\)

B  \(\frac{{x + 2}}{{ - 1}} = \frac{{y - 3}}{5}\)

C \(\left\{ \begin{array}{l}x =  - 2 + 5t\\y = 3 - t\end{array} \right.(t \in R)\)

D \(5x + y - 13 = 0\)

A \(\frac{{x + 2}}{5} = \frac{{y - 3}}{{ - 1}}\)

B \(\left\{ \begin{array}{l}x =  - 2 + 5t\\y = 3 - t\end{array} \right.(t \in R)\)

C \(x + 5y - 13 = 0\)

D \(5x + y - 13 = 0\)

A \(\frac{{x + 2}}{5} = \frac{{y - 3}}{{ - 1}}\)

B \(\left\{ \begin{array}{l}x =  - 2 + 5t\\y = 3 - t\end{array} \right.(t \in R)\)

C \(x + 5y - 13 = 0\)

D \(5x + y - 13 = 0\)

A \(\frac{{x + 2}}{5} = \frac{{y - 3}}{{ - 1}}\)

B \(\left\{ \begin{array}{l}x = 2 + 5t\\y = 1 - t\end{array} \right.(t \in R)\)

C \(x + 5y - 13 = 0\)

D \(\left\{ \begin{array}{l}x =  - 1 + 3t\\y = 2 + 2t\end{array} \right.\)

A \(3x - 4y - 4 = 0\)

B  \(\left\{ \begin{array}{l}x = 2 + 3t\\y = 1 - 4t\end{array} \right.(t \in R)\)

C \(4x + 4y - 1 = 0\)

D \(4x + 3y - 4 = 0\)

A \(5x+2y-6=0\)

B \(-2x+5y-16=0\)

C \(5x+2y-16=0 \)

D \(4x-10y+8=0\)

A \(\left\{ {\begin{array}{*{20}{c}}{x = 2 + t}\\{y =  - 1 - 2t}\end{array}} \right.\)

B \(2x + y + 8 = 0\)  

C \(x - 2y + 8 = 0\)  

D \(\frac{{x + 2}}{5} = \frac{{y - 3}}{{ - 1}}\)

A \(6x-y+26=0\)

B \(6x-10y+2=0\)

C \(x-10y+6=0\)

D \(6x-10y+26=0\)

A \(5x-8y+6=0\)

B \(7x-5y+6=0\)

C \(10x-13y+25=0\)

D \(x-18y+7=0\)

A \(7x+2y-38=0\)

B \(2x-7y+25=0\)

C \(7x-13y+6=0\)

D \(5x-3y+23=0\)

A \(5x+3y-1=0\)

B \(2x+3y-13=0\)

C \(15x+6y-1=0\)

D \(5x-3y-1=0\)

A \(3x-y + 9= 0\)

B \( 5x+ y + 7 = 0\)

C \(y + 7 = 0\)

D \(x-y+7=0\)

A \(4x-2y -9=0\)

B \(x-2y+5 =0\)

C \(x-2y=0\)

D \(x-y+9=0\)

A \(H\left( {\frac{{14}}{5};\frac{{17}}{5}} \right)\)

B \(H\left( {1;\frac{{17}}{5}} \right)\)

C \(H\left( {1;\,\,2} \right)\)

D \(H\left( {6;\,\,9} \right)\)

A \(A'\left( \frac{14}{5};\frac{17}{5} \right)\)

B \(A'\left( \frac{8}{5};\frac{29}{5} \right)\)

C \(A'\left( 1;\frac{17}{5} \right)\)

D A’(6;9)

A \(7x-2y -9=0\)

B \(8x-4y+5 =0\)

C \(2x-7y+12=0\)

D \(7x-y+1=0\)