A.\[\mathop \smallint \limits_a^b f'\left( x \right){e^{f\left( x \right)}}dx = 0\]
B.\[\mathop \smallint \limits_a^b f'\left( x \right){e^{f\left( x \right)}}dx = 1\]
C.\[\mathop \smallint \limits_a^b f'\left( x \right){e^{f\left( x \right)}}dx = - 1\]
D. \[\mathop \smallint \limits_a^b f'\left( x \right){e^{f\left( x \right)}}dx = 2\]
A.\[\mathop \smallint \limits_{ - 1}^2 f\left( {2x} \right)d{\rm{x}} = 2\]
B. \[\mathop \smallint \limits_{ - 3}^3 f\left( {x + 1} \right)d{\rm{x}} = 2\]
C. \[\mathop \smallint \limits_{ - 1}^2 f\left( {2x} \right)d{\rm{x}} = 1\]
D. \[\mathop \smallint \limits_0^6 \frac{1}{2}f\left( {x - 2} \right)d{\rm{x}} = 1\]
A.\[\mathop \smallint \limits_{ - a}^a f\left( x \right)dx = 0\]
B. \[\mathop \smallint \limits_{ - a}^a f\left( x \right)dx = 1\]
C. \[\mathop \smallint \limits_{ - a}^a f\left( x \right)dx = - 1\]
D. \[\mathop \smallint \limits_{ - a}^a f\left( x \right)dx = a\]
A.\[I = \frac{{ - 1}}{2}\]
B. \[I = - \frac{1}{4}\]
C. \[I = \frac{1}{4}\]
D. \[I = - 2\]
A.\[I = - \frac{1}{4}{\pi ^4}\]
B. \[I = - {\pi ^4}\]
C. \[I = 0\]
D. \[I = - \frac{1}{4}\]Trả lời:
A.\[I = \left( {\frac{{{u^3}}}{3} + u} \right)\left| {_1^2} \right.\]
B. \[I = \frac{4}{3}\left( {{u^3} + u} \right)\left| {_1^2} \right.\]
C. \[I = 2\left( {\frac{{{u^3}}}{3} + u} \right)\left| {_1^2} \right.\]
D. \[I = \frac{1}{3}\left( {\frac{{{u^3}}}{3} + u} \right)\left| {_1^2} \right.\]
A.\[I = 2\mathop \smallint \limits_8^9 \sqrt u du\]
B. \[I = \frac{1}{2}\mathop \smallint \limits_8^9 \sqrt u du\]
C. \[I = \mathop \smallint \limits_9^8 \sqrt u du\]
D. \[I = \mathop \smallint \limits_8^9 \sqrt u du\]
A.\[ - \frac{2}{3}\]
B. \[4\sqrt 3 - 1\]
C. \[\frac{{2\sqrt 3 }}{3}\]
D. Kết quả khác
A.\[a = 2\]
B. \[a = \frac{1}{2}\]
C. \[a = \sqrt 2 \]
D. \[a = 4\]
A.\[I = \frac{2}{3}\mathop \smallint \limits_1^2 tdt\]
B. \[I = \frac{2}{3}\mathop \smallint \limits_1^2 {t^2}dt\]
C. \[I = \left( {\frac{2}{9}{t^3} + 2} \right)\left| {_1^2} \right.\]
D. \[I = \frac{{14}}{9}\]
A.\[I = \mathop \smallint \limits_1^0 \left( {1 - u} \right)du\]
B. \[I = \mathop \smallint \limits_0^1 \left( {1 - u} \right){e^{ - u}}du\]
C. \[I = \mathop \smallint \limits_1^0 \left( {1 - u} \right){e^{ - u}}du\]
D. \[I = \mathop \smallint \limits_1^0 \left( {1 - u} \right){e^{2u}}du\]
A.\[I = - \mathop \smallint \limits_{\sqrt 2 }^{\frac{2}{{\sqrt 3 }}} \frac{{{t^2}}}{{{t^2} - 1}}dt\]
B. \[I = \mathop \smallint \limits_2^3 \frac{{{t^2}}}{{{t^2} + 1}}dt\]
C. \[I = \mathop \smallint \limits_{\sqrt 2 }^{\frac{2}{{\sqrt 3 }}} \frac{{{t^2}}}{{{t^2} - 1}}dt\]
D. \[I = \mathop \smallint \limits_2^3 \frac{t}{{{t^2} + 1}}dt\]
A.\[2a + b = 1\]
B. \[{a^2} + {b^2} = 4\]
C. \[a - b = 1\]
D. \[ab = \frac{1}{2}\]
A.\[I = - 16\mathop \smallint \limits_0^{\frac{\pi }{4}} {\cos ^2}tdt\]
B. \[I = 8\mathop \smallint \limits_0^{\frac{\pi }{4}} \left( {1 + \cos 2t} \right)dt\]
C. \[I = 16\mathop \smallint \limits_0^{\frac{\pi }{4}} {\sin ^2}tdt\]
D. \[I = 8\mathop \smallint \limits_0^{\frac{\pi }{4}} \left( {1 - \cos 2t} \right)dt\]
A.\[I = \mathop \smallint \limits_0^{\frac{\pi }{6}} dt\]
B. \[I = \mathop \smallint \limits_0^{\frac{\pi }{6}} tdt\]
C. \[I = \mathop \smallint \limits_0^{\frac{\pi }{6}} \frac{{dt}}{t}\]
D. \[I = \mathop \smallint \limits_0^{\frac{\pi }{3}} dt\]
A.\[a = 1\]
B. \[a = - \frac{1}{3}\]
C. \[a = 2\]
D. \[a = --2\]
A.\[I = \frac{1}{2}\mathop \smallint \limits_0^1 {e^t}\left( {1 - t} \right)dt\]
B. \[I = 2\left[ {\mathop \smallint \limits_0^1 {e^t}dt + \mathop \smallint \limits_0^1 t{e^t}dt} \right]\]
C. \[I = 2\mathop \smallint \limits_0^1 {e^t}\left( {1 - t} \right)dt\]
D. \[I = \frac{1}{2}\mathop \smallint \limits_0^1 {e^t}\left( {1 - {t^2}} \right)dt\]Trả lời:
A.\[\frac{{13}}{{9\pi }}\]
B. \[\frac{{14}}{9}\]
C. \[\frac{{14}}{{9\pi }}\]
D. \[\frac{{14\pi }}{9}\]
A.\[S = 6\]
B. \[S = 5\]
C. \[S = 7\]
D. \[S = 8\]
A.\(\frac{1}{2}\)
B. \( - \frac{1}{2}\)
C. 2
D. -2
A.\[I = \frac{{14}}{3}\]
B. \[I = \frac{{28}}{3}\]
C. \[I = \frac{4}{3}\]
D. \[I = 2\]
A.\[I = 5\]
B. \[I = \frac{5}{2}\pi \]
C. \[I = 5\pi \]
D. \[I = 10\pi \]
A.3(1−e)
B.3e
C.0
D.3(e−1)
A.\[I = 6.\]
B. \[I = 4.\]
C. \[I = 10.\]
D. \[I = 2.\]
A.\[78\pi \]
B. \[650\pi \]
C. \[325\pi \]
D. \[39\pi \]
A.\[\frac{2}{3}.\]
B. 4
C. \[\frac{3}{2}.\]
D. 6
A.\[\sqrt {11} - \sqrt 5 \]
B. 6
C. \[\sqrt 5 - \sqrt {11} \]
D. 3
A.16160
B.4040
C.2020
D.8080
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