A.x=4.
B.x=2.
C.x=5.
D.x=3.
A.x=5
B.x=4
C.x=6
D.x=17
A.\[\frac{{ - 8}}{5}\]
B. 3
C. \[\frac{8}{5}\]
D. \[\frac{{12}}{5}\]
A.\[(--\infty ;--3)\]
B. \[(--3; + \infty )\]
C. \[(3; + \infty )\]
D. \[(0; + \infty )\]
A.T=2.
B.T=3.
C.\[T = \frac{{13}}{4}\]
D. \[T = \frac{1}{4}\]
A.\[S = \{ 1\} \]
B. \[S = \{ 3\} \]
C. \[S = \{ 2\} \]
D. \[S = \{ 5\} \]
A.\[\left\{ { - 1;2} \right\}.\]
B. \[\left\{ {0;1} \right\}.\]
C. \[\left\{ { - 1;0} \right\}.\]
D. \[\left\{ { - 2;1} \right\}.\]
A.−13<m<−9
B.3<m<9
C.−9<m<3
D. −13<m<3
A.\[\left( { - \infty ;1} \right)\]
B. \[\left[ {2; + \infty } \right)\]
C. \[\left( { - \infty ;1} \right) \cup \left( {2; + \infty } \right)\]
D. \[\left( {2; + \infty } \right)\]
A.\[m \in (\frac{{17}}{{16}};\frac{5}{2})\]
B. \[m \in [2;4]\]
C. \[m \in (\frac{5}{2};6)\]
D. \[m \in (1;\frac{5}{2})\]
A.\[\left\{ {1;{{\log }_3}2} \right\}\]
B. \[\left\{ { - 2;3} \right\}\]
C. \[\left\{ 1 \right\}\]
D. \[\left\{ 3 \right\}\]
A.m>1
B.m<−1
C.m<0
D.−1<m<0
A.m=3
B.m=18
C.\[m = \frac{1}{8}\]
D.m=1
A.\[2 = {3^{{{\log }_5}x}}\]
B. \[5 = {x^{{{\log }_2}3}}\]
C. \[2 = {x^{{{\log }_3}5}}\]
D. \[3 = {5^{\log x}}\]
A.\[P = \frac{1}{2}\,\]
B. \[P = 1 - {\log _{\frac{9}{2}}}2\,\]
C. \[P = 1\]
D. \[P = 1 - \frac{1}{2}{\log _{\frac{9}{2}}}2\]
A.2
B.−1
C.0
D.1
A.\[m = \frac{5}{2}\]
B. \[m = \frac{3}{2}\]
C. m=3
D. m=2
A.3
B.2
C.0
D.1
A.\[{x^{\frac{2}{3}}} + 5 = 0\]
B. \[{(3x)^{\frac{1}{3}}} + {\left( {x - 4} \right)^{\frac{2}{5}}} = 0\]
C. \[\sqrt {4x - 8} + 2 = 0\]
D. \[2{x^{\frac{1}{2}}} - 3 = 0\]
A.1
B.2
C.3
D.
A.\[\alpha = 1\]
B. \[\alpha \in R\]
C. \[\alpha = 0\]
D. \[\alpha = - 1\]
A.7
B.3
C.5
D.6
A.\[ - 1 + 2{\log _2}3\]
B. \[1 + {\log _2}3\]
C. -1
D. \[1 + 2{\log _2}3\]
A.0
B.2
C.\( - \frac{1}{2}\)
D. \(\frac{1}{2}\)
A.0,50
B.0,35
C.0,40
D.0,45
A.\[{e^4}\]
B. \[{e^3}\]
C. \[{e^{\frac{{15}}{{13}}}}\]
D. \[{e^5}\]
A.\[\frac{1}{3}{\log _5}2020.\]
B. \[\frac{1}{6}{\log _5}2018.\]
C. \[\frac{1}{6}{\log _5}2020.\]
D. \[\frac{1}{2}{\log _5}2018.\]
A.1
B.2
C.4
D.3
A.10
B.−8
C.8
D.−10
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