Trắc nghiệm Hình học 12 Chương 3 Phương pháp tọa độ trong không gian

A. \(Q=1\)  

B. \(Q=\frac{1}{3}\)

C. \(Q=2\)

D. \(Q=3\)

A.  I(2;4;-1)

B. I(1;2;0)

C.  I(1;0;0)

D. I(0;0;1)

A. (-1;0;1)

B. (-2;0;2)

C.  (-1;1;0)

D. (-2;2;0)

A.  \(m\neq 0\)

B.  \(m=0\)

C.  \(m\in \mathbb{R}\)

D. Không có giá trị nào của m

A. \((P):2x - 2y + z - 8 = 0\)

B. \((P): - 2x + 11y - 10z - 105 = 0\)

C. \((P): - 2x + 2y - z + 11 = 0\)

D. \((P):2x - 11y + 10z - 35 = 0\)

A.  \(\left\{ \begin{array}{l} x = 0\\ y = - 1 - t\\ z = 0 \end{array} \right.\)

B.  \(\left\{ \begin{array}{l} x = 1 + 2t\\ y = - 1 + t\\ z = 0 \end{array} \right.\) 

C.  \(\left\{ \begin{array}{l} x = - 1 + 2t\\ y = 1 + t\\ z = 0 \end{array} \right.\)

D.  \(\left\{ \begin{array}{l} x = - 1 + 2t\\ y = - 1 + t\\ z = 0 \end{array} \right.\)

A. \(\left( P \right):x - 7y - 4z + 9 = 0\) 

B.  \(\left( P \right):3x - 5y - 4z + 9 = 0\)

C.  \(\left( P \right):2x - 5y - 3z + 8 = 0\)

D. \(\left( P \right):4x - 3y - 2z + 7 = 0\)

A. \({\left( {x - 1} \right)^2} + {y^2} + {\left( {z - 2} \right)^2} = 3\)

B.  \({\left( {x + 1} \right)^2} + {y^2} + {\left( {z + 2} \right)^2} = 3\)

C. \({\left( {x - 1} \right)^2} + {y^2} + {\left( {z - 2} \right)^2} = 19\)

D. \({\left( {x - 1} \right)^2} + {y^2} + {\left( {z - 2} \right)^2} = 9\)

A.  \(M\left( { - 7;3;2} \right)\)

B.  \(M\left( { 2;3;-7} \right)\)

C.  \(M\left( { 3;2;-7} \right)\)

D.  \(M\left( { 3;-7;2} \right)\)

A. \(\left( S \right):{\left( {x - 1} \right)^2} + {\left( {y - 3} \right)^2} + {z^2} = 9\)

B. \(\left( S \right):{\left( {x - 1} \right)^2} + {\left( {y - 3} \right)^2} + {\left( {z - 2} \right)^2} = 9\)

C. \(\left( S \right):{\left( {x - 1} \right)^2} + {\left( {y - 3} \right)^2} + {\left( {z + 2} \right)^2} = 9\)

D. \(\left( S \right):{\left( {x - 1} \right)^2} + {\left( {y + 3} \right)^2} + {\left( {z + 2} \right)^2} = 9\)

A. \(M\left( { - 2; - 3;3} \right)\)

B. \(M\left( { - 2; - 3;2} \right)\)

C. \(M\left( { - 2; - 3;6} \right)\)

D. \(M\left( { - 2; - 3;0} \right)\)

A. \( D\left( {0;0;0} \right)\) và \(D\left( { - 6;0;0} \right)\)

B. \( D\left( {0;0;0} \right)\)và \(D\left( { 6;0;0} \right)\)

C. \( D\left( {0;0;2} \right)\) và \(D\left( { 6;0;0} \right)\)

D. \( D\left( {0;0;1} \right)\) và \(D\left( { 6;0;0} \right)\)

A. \(\frac{{\sqrt {491} }}{2}\)

B. \(\frac{{\sqrt {490} }}{2}\)

C. \(\frac{{\sqrt {494} }}{2}\)

D. \(\frac{{\sqrt {394} }}{2}\)

A. \(B'\left( {2;3;2} \right)\)

B. \(B'\left( {2;3;0} \right)\)

C. \(B'\left( {2;3;1} \right)\)

D. \(B'\left( {2;3; - 1} \right)\)

A. \(C'\left( {2;2;2} \right)\)

B. \(C'\left( {2;-2; - 2} \right)\)

C. \(C'\left( {2; - 2;2} \right)\)

D. \(C'\left( {-2; - 2;-2} \right)\)

A. \({x^2} + {y^2} + {z^2} - 3x - 3y + 3z + 6 = 0\)

B. \({x^2} + {y^2} + {z^2} + 3x - 3y - 3z + 6 = 0\)

C. \({x^2} + {y^2} + {z^2} - 3x - 3y - 3z + 6 = 0\)

D. \({x^2} + {y^2} + {z^2} - 3x - 3y - 3z - 6 = 0\)

A. \({\left( {x - 2} \right)^2} + {\left( {y + 3} \right)^2} + {\left( {z + 2} \right)^2} = 9\)

B. \({\left( {x - 2} \right)^2} + {\left( {y - 3} \right)^2} + {\left( {z + 2} \right)^2} = 9\)

C. \({\left( {x - 2} \right)^2} + {\left( {y - 3} \right)^2} + {\left( {z - 2} \right)^2} = 9\)

D. \({\left( {x + 2} \right)^2} + {\left( {y - 3} \right)^2} + {\left( {z + 2} \right)^2} = 9\)

A. \(x - 2y - 2z + 9 = 0\)

B. \(x - 2y + 2z + 9 = 0\)

C. \(x + 2y - 2z + 9 = 0\)

D. \(x - 2y - 2z - 9 = 0\)

A. \( - x + 2y - 2 = 0\)

B. \( - x + 2y - 1 = 0\)

C. \( - x - 2y - 2 = 0\)

D. \( - x + 2y - 3 = 0\)

A. \(N\left( {4;3;3} \right)\)

B. \(N\left( {4;3;0} \right)\)

C. \(N\left( {4;-3;-3} \right)\)

D. \(N\left( {4;3;-3} \right)\)

A. \(H\left( {3; - 3;1} \right)\)

B. \(H\left( { - 3;3;1} \right)\)

C. \(H\left( {3;3;1} \right)\)

D. \(H\left( {3;3; - 1} \right)\)

A. \(\left\{ \begin{array}{l} x = - 5 + t\\ y = 1 + 2t\\ z = 13 + t \end{array} \right.\)

B. \(\left\{ \begin{array}{l} x = - 5 + t\\ y = 1 + 2t\\ z = - 13 + t \end{array} \right.\)

C. \(\left\{ \begin{array}{l} x = - 5 + t\\ y = - 1 + 2t\\ z = 13 + t \end{array} \right.\)

D. \(\left\{ \begin{array}{l} x = - 5 + t\\ y = 1 + 2t\\ z = 13 - t \end{array} \right.\)

A. \(x - y - z - 7 = 0\)

B. \(x - y + z + 7 = 0\)

C. \(x - y - z + 7 = 0\)

D. \(x + y - z + 7 = 0\)

A. \({\left( {x - 2} \right)^2} + {y^2} + {\left( {z - 1} \right)^2} = 4\)

B. \({\left( {x - 2} \right)^2} + {y^2} + {\left( {z - 2} \right)^2} = 4\)

C. \({\left( {x - 2} \right)^2} + {y^2} + {\left( {z + 1} \right)^2} = 4\)

D. \({\left( {x + 2} \right)^2} + {y^2} + {\left( {z - 1} \right)^2} = 4\)

A. \(\left\{ \begin{array}{l} x = 2 - t\\ y = 0\\ z = 2 + t \end{array} \right.,t \in R\)

B. \(\left\{ \begin{array}{l} x = 2 - t\\ y = 1\\ z = 1 + t \end{array} \right.,t \in R\)

C. \(\left\{ \begin{array}{l} x = 2 - t\\ y = 0\\ z = 1 + t \end{array} \right.,t \in R\)

D. \(\left\{ \begin{array}{l} x = 1 - t\\ y = 0\\ z = 1 + t \end{array} \right.,t \in R\)

A. \({\left( {x - 7} \right)^2} + {\left( {y - 4} \right)^2} + {\left( {z + 6} \right)^2} = 4\)

B. \({\left( {x - 7} \right)^2} + {\left( {y + 4} \right)^2} + {\left( {z - 6} \right)^2} = 4\)

C. \({\left( {x - 7} \right)^2} + {\left( {y - 4} \right)^2} + {\left( {z - 6} \right)^2} = 4\)

D. \({\left( {x + 7} \right)^2} + {\left( {y - 4} \right)^2} + {\left( {z - 6} \right)^2} = 4\)

A. \(H\left( {\frac{{19}}{3};\frac{8}{3};\frac{{22}}{3}} \right)\)

B. \(H\left( {\frac{{19}}{3};\frac{8}{3};\frac{{23}}{3}} \right)\)

C. \(H\left( {\frac{{19}}{3};\frac{8}{3};\frac{{25}}{3}} \right)\)

D. \(H\left( {\frac{{19}}{3};\frac{{17}}{3};\frac{{22}}{3}} \right)\)