A.
\(\overrightarrow{b}=\left( -2;6;8 \right)\).
B.
\(\overrightarrow{b}=\left( -2;-6;-8 \right)\).
C.
\(\overrightarrow{b}=\left( -2;-6;8 \right)\).
D. \(\overrightarrow{b}=\left( 2;-6;-8 \right)\).
A. \(\left( 3;\,3;\,-1 \right)\)
B. \(\left( -1;\,-1;\,-3 \right)\).
C. \(\left( 3;\,1;\,1 \right)\).
D. \(\left( 1;\,1;\,3 \right)\)
A. \(M\left( 0;\,0;\,1 \right)\).
B. \(M\left( 2;\,-4;\,-1 \right)\).
C. \(M\left( 4;\,0;\,3 \right)\).
D. \(M\left( 0;\,-1;\,0 \right)\).
A. \(\overrightarrow{n}=\left( 2;4;3 \right)\).
B. \(\overrightarrow{n}=\left( 2;4;-3 \right)\).
C. \(\overrightarrow{n}=\left( 2;-4;-3 \right)\)
D. \(\overrightarrow{n}=\left( -3;4;2 \right)\)
A. \(B\,\left( -3\,;\,2\,;\,0 \right)\).
B. \(D\,\left( 1\,;\,2\,;\,-6 \right)\).
C. \(A\,\left( -1\,;\,-4\,;\,1 \right)\).
D. \(C\,\left( -1\,;\,-2\,;\,1 \right)\)
A.
\({{\left( x-1 \right)}^{2}}+{{y}^{2}}+{{\left( z-1 \right)}^{2}}=1\).
B.
\({{\left( x-1 \right)}^{2}}+{{y}^{2}}+{{\left( z-1 \right)}^{2}}=4\)
C. \({{\left( x-3 \right)}^{2}}+{{\left( y-1 \right)}^{2}}+{{\left( z+2 \right)}^{2}}=1\).
D. \({{\left( x-3 \right)}^{2}}+{{\left( y-1 \right)}^{2}}+{{\left( z+2 \right)}^{2}}=4\)
A. \(x=4\) và \(y=7\)
B. \(x=-4\) và \(y=-7\).
C. \(x=4\) và \(y=-7\)).
D. \(x=-4\) và \(y=7\)
A.
\(\left[ \begin{array}{l}
D\left( {0{\rm{ }};{\rm{ }}5{\rm{ }};0} \right)\\
D\left( {0{\rm{ }}; - 4{\rm{ }};{\rm{ }}0} \right)
\end{array} \right.\)
B.
\(\left[ {\begin{array}{*{20}{l}}
{D\left( {0;{\rm{8}};0} \right)}\\
{D\left( {0; - 7;0} \right)}
\end{array}} \right.\)
C. \(D\left( 0\text{ };-7\text{ };\text{ }0 \right)\).
D. \(D\left( 0\text{ };8\text{ };\text{ }0 \right)\)
A. \(I=\left( 1\,;\,-2\,;\,-1 \right)\).
B. \(I=\left( -1\,;\,-2\,;\,-1 \right)\).
C. \(I=\left( 1\,;\,-2\,;\,1 \right)\).
D. \(I=\left( -1\,;\,-2\,;\,-1 \right)\).
A. \(R=4\).
B. \(R=1\).
C. \(R=2\)
D. \(R=3\sqrt{2}\)
A.
\({{x}^{2}}+{{y}^{2}}+{{z}^{2}}-2x-2y-2z-8=0\)
B.
\({{\left( x+1 \right)}^{2}}+{{\left( y-2 \right)}^{2}}+{{\left( z-1 \right)}^{2}}=9\)
C. \(2{{x}^{2}}+2{{y}^{2}}+2{{z}^{2}}-4x+2y+2z+16=0\)
D. \(3{{x}^{2}}+3{{y}^{2}}+3{{z}^{2}}-6x+12y-24z+16=0\)
A. \(S=\frac{2\pi \sqrt{78}}{3}\)
B. \(S=2\pi \sqrt{6}\).
C. \(S=6\pi \).
D. \(S=\frac{26\pi }{3}\)
A.
\(\left( S \right):{{x}^{2}}+{{\left( y-1 \right)}^{2}}+{{\left( z-2 \right)}^{2}}=29\)
B.
\(\left( S \right):{{x}^{2}}+{{\left( y-1 \right)}^{2}}+{{\left( z-2 \right)}^{2}}=\sqrt{29}\).
C. \(\left( S \right):{{x}^{2}}+{{\left( y+1 \right)}^{2}}+{{\left( z+2 \right)}^{2}}=841\)
D. \(\left( S \right):{{x}^{2}}+{{\left( y+1 \right)}^{2}}+{{\left( z+2 \right)}^{2}}=29\).
A.
\({{x}^{2}}+{{y}^{2}}+{{z}^{2}}-z-5=0\)
B.
\({{x}^{2}}+{{y}^{2}}+{{z}^{2}}+5=0\)
C. \({{x}^{2}}+{{y}^{2}}+{{z}^{2}}-x-5=0\).
D. \({{x}^{2}}+{{y}^{2}}+{{z}^{2}}-y-5=0\).
A.
\({{\left( x+1 \right)}^{2}}+{{\left( y+2 \right)}^{2}}+{{\left( z-1 \right)}^{2}}=5\).
B.
\({{\left( x-1 \right)}^{2}}+{{\left( y-2 \right)}^{2}}+{{\left( z+1 \right)}^{2}}=9\)
C. \({{\left( x-1 \right)}^{2}}+{{\left( y-2 \right)}^{2}}+{{\left( z+1 \right)}^{2}}=25\).
D. \({{\left( x+1 \right)}^{2}}+{{\left( y+2 \right)}^{2}}+{{\left( z-1 \right)}^{2}}=3\).
A. \(G\left( 6;-7;1 \right)\).
B. \(G\left( 3;-1;-2 \right)\).
C. \(G\left( 3;1;-2 \right)\).
D. \(G\left( -3;1;2 \right)\). \(G\left( -3;1;2 \right)\).
A. \(2x+3y+4=0\).
B. \(x-2y+2z-8=0\).
C. \(x-2y+2z+8=0\)
D. \(x-2y+2z+4=0\)
A. 1
B. \(\frac{11}{3}\).
C. \(\frac{1}{3}\)
D. 3
A. \(\overrightarrow{{{n}_{1}}}=\left( 1;2;0 \right).\)
B. \(\overrightarrow{{{n}_{2}}}=\left( 1;2;2 \right).\)
C. \(\overrightarrow{{{n}_{3}}}=\left( 1;8;2 \right).\)
D. \(\overrightarrow{{{n}_{4}}}=\left( 1;-2;2 \right).\)
A.
\(\left( Q \right):2x+2y-z+10=0\)
B.
\(\left( Q \right):2x+2y-z+4=0\)
C. \(\left( Q \right):2x+2y-z+8=0\)
D. \(\left( Q \right):2x+2y-z-8=0\).
A. \(P\left( 1;-1;1 \right)\).
B. \(N\left( 0;1;1 \right)\).
C. \(Q\left( 1;1;1 \right)\).
D. \(M\left( 2;1;-1 \right)\).
A. T=3
B. T=6
C. T=0
D. T=9
A.
\(\left[ \begin{array}{l}
D\left( {0;0;0} \right)\\
D\left( {6;0;0} \right)
\end{array} \right..\)
B. \(D\left( 0;-6;0 \right).\)
C.
\(\left[ \begin{array}{l}
D\left( {0;0;0} \right)\\
D\left( { - 6;0;0} \right)
\end{array} \right..\)
D. \(D\left( 6;0;0 \right).\)
Lời giải có ở chi tiết câu hỏi nhé! (click chuột vào câu hỏi).
Copyright © 2021 HOCTAPSGK