Đề thi giữa HK1 môn Toán 11 năm 2019 - 2020 Trường THPT Lê Khiết

A. y= sin \(\sqrt x \) 

B. y = \(\frac{1}{{2 - {\rm{ cos}}x}}\)

C. y= tan2 x

D. y = \(\frac{{1 - {\mathop{\rm s}\nolimits} {\rm{in}}x}}{{1 + {\rm{ sin}}x}}\)

A. \(0 \le a \le 2;{\rm{ a}} \ne {\rm{1}}\)

B. \(\left[ \begin{array}{l}
a \le 0\\
a \ge 2
\end{array} \right.\)

C. \(a \ge 2\)

D. \(a \le 0\)

A. 2021

B. 2020

C. 4038

D. 4040

A. \(\left[ {\begin{array}{*{20}{l}} {x = \frac{\pi }{3} + k2\pi }\\ {x = \frac{{2\pi }}{3} + k2\pi } \end{array}} \right.,\left( {k \in Z} \right)\)

B.

\(\left[ \begin{array}{l}
{\rm{ x  =  k2}}\pi \\
{\rm{x  = }}\frac{{2\pi }}{3} + {\rm{k2}}\pi 
\end{array} \right.,\left( {{\rm{k}} \in Z} \right)\)

C. \(\left[ {\begin{array}{*{20}{l}} {{\rm{x = k}}\pi }\\ {{\rm{x = }}\frac{{2\pi }}{3} + {\rm{k}}\pi } \end{array}} \right.,\left( {{\rm{k}} \in Z} \right)\)

D. \(\left[ \begin{array}{l}
{\rm{ x  =  }}\frac{\pi }{6}{\rm{ + k2}}\pi \\
{\rm{x  = }}\frac{{5\pi }}{6} + {\rm{k2}}\pi 
\end{array} \right.,\left( {{\rm{k}} \in Z} \right)\)

A. \(\frac{\pi }{4}\)

B. \(\frac{{7\pi }}{4}\)

C. \(\frac{{3\pi }}{4}\) 

D. \(-\frac{\pi }{4}\)

A. \(\left[ \begin{array}{l}
x = {\rm{ k}}\pi \\
x{\rm{  = }}\frac{\pi }{6} + {\rm{k2}}\pi 
\end{array} \right.,{\rm{ }}({\rm{k}} \in Z)\)

B. \(\left[ \begin{array}{l}
x = {\rm{ k}}\pi \\
x{\rm{  = }} \pm \frac{\pi }{3} + {\rm{k2}}\pi 
\end{array} \right.,{\rm{ }}({\rm{k}} \in Z)\)

C. \(\left[ \begin{array}{l}
x = {\rm{ k}}\pi \\
x{\rm{  = }} \pm \frac{\pi }{6} + {\rm{k2}}\pi 
\end{array} \right.,{\rm{ }}({\rm{k}} \in Z)\)

D. \(\left[ \begin{array}{l}
x = {\rm{ k2}}\pi \\
x{\rm{  = }} \pm \frac{\pi }{6} + {\rm{k2}}\pi 
\end{array} \right.,{\rm{ }}({\rm{k}} \in Z)\)

A. y = tan \(\left( {\frac{x}{2}} \right)\)

B. y = sin2x

C. y = cos \(\left( {\frac{x}{2}} \right)\)

D. y = cot2x

A. \(x{\rm{  = }}\frac{{{\rm{ k}}\pi }}{2},{\rm{ }}\left( {{\rm{k}} \in Z} \right)\)

B. \(x{\rm{  =  k}}\pi ,{\rm{ }}\left( {{\rm{k}} \in Z} \right)\)

C. \(x{\rm{  = }}\frac{{{\rm{ k}}\pi }}{8},{\rm{ }}\left( {{\rm{k}} \in Z} \right)\)

D. \(x{\rm{  = }}\frac{{{\rm{ k}}\pi }}{4},{\rm{ }}\left( {{\rm{k}} \in Z} \right)\)

A. 0

B. 2

C. 3

D. 1