A. 0
B. -4
C. 2
D. -2
A. 10
B. -8
C. -35
D. -7
A. \(4\sqrt 2\)
B. 4
C. \(8\sqrt 2\)
D. 8
A. \(\left| \omega \right| = \sqrt {229}\)
B. \(\left| \omega \right| = \sqrt {13}\)
C. \(\left| \omega \right| = 229\)
D. \(\left| \omega \right| = 13\)
A. 2
B. 4
C. 3
D. 5
A. 10
B. 11
C. 9
D. 8
A. 1094
B. 3281
C. 1093
D. 3280
A. 5
B. 1010
C. 6
D. 2020
A. \(\frac{1}{6}\)
B. \(\frac{7}{{36}}\)
C. \(\frac{2}{9}\)
D. \(\frac{5}{{36}}\)
A. 0.09
B. 0.08
C. 0.19
D. 0.18
A. \(\frac{1}{3}\)
B. \(\frac{3}{5}\)
C. \(\frac{3}{{10}}\)
D. \(\frac{9}{{25}}\)
A. \(\frac{5}{{36}}\)
B. \(\frac{5}{9}\)
C. \(\frac{5}{{18}}\)
D. \(\frac{1}{9}\)
A. \(\frac{9}{{25}}\)
B. \(\frac{1}{3}\)
C. \(\frac{3}{{10}}\)
D. \(\frac{3}{5}\)
A. \(\frac{{13}}{{27}}\)
B. \(\frac{{14}}{{27}}\)
C. \(\frac{1}{2}\)
D. \(\frac{{365}}{{729}}\)
A. \(\frac{7}{{15}}\)
B. \(\frac{8}{{15}}\)
C. \(\frac{2}{5}\)
D. \(\frac{3}{5}\)
A. -2
B. 12
C. 22
D. 2
A. 5
B. 1
C. 7
D. 3
A. 8
B. 14
C. 15
D. 11
A. \(\frac{7}{3}\)
B. \(\frac{5}{2}\)
C. \(\frac{5}{3}\)
D. 2
A. 4
B. 0
C. 2
D. -4
A. -1
B. 2021
C. 1
D. -2021
A. 6
B. 4
C. 8
D. 2
A. \(– \frac{2}{{2019}}\)
B. – 4038
C. \(\frac{2}{{2019}}\)
D. 4038
A. 40
B. -20
C. 20
D. -40
A. I = 16
B. I = 18
C. I = 8
D. I = 20
A. \(\frac{{x – 1}}{2} = \frac{{y + 3}}{{ – 4}} = \frac{{z + 2}}{1}\)
B. \(\frac{{x + 1}}{{ – 2}} = \frac{{y – 3}}{{ – 2}} = \frac{{z – 2}}{{ – 4}}\)
C. \(\frac{{x + 1}}{2} = \frac{{y – 3}}{{ – 4}} = \frac{{z – 2}}{1}\)
D. \(\frac{{x – 2}}{{ – 1}} = \frac{{y + 4}}{3} = \frac{{z – 1}}{2}\)
A. \(d:\left\{ \begin{array}{l}x = 0\\y = 2t\\z = 3t\end{array} \right.\)
B. \(d:\left\{ \begin{array}{l}x = – t\\y = – 2t\\z = – 3t\end{array} \right.\)
C. \(d:\left\{ \begin{array}{l}x = 1\\y = 2\\z = 3\end{array} \right.\)
D. \(d:\left\{ \begin{array}{l}x = t\\y = 3t\\z = 2t\end{array} \right.\)
A. \(\Delta :\left\{ \begin{array}{l}x = 1 + 3t\\y = – 3 + 2t\\z = – 2 + 2t\end{array} \right.\)
B. \(\Delta :\left\{ \begin{array}{l}x = 1 + 4t\\y = – 3 – t\\z = – 2\end{array} \right.\)
C. \(\Delta :\left\{ \begin{array}{l}x = 3 + 4t\\y = 2 – t\\z = 2\end{array} \right.\)
D. \(\Delta :\left\{ \begin{array}{l}x = 3 – t\\y = 2 + 3t\\z = 2 + 2t\end{array} \right.\)
A. \(\left\{ \begin{array}{l}x = 0\\y = 1\\z = t\end{array} \right.\)
B. \(\left\{ \begin{array}{l}x = 0\\y = t\\z = 0\end{array} \right.\)
C. \(\left\{ \begin{array}{l}x = t\\y = 0\\z = 0\end{array} \right.\)
D. \(\left\{ \begin{array}{l}x = 0\\y = 0\\z = t\end{array} \right.\)
A. \(\frac{{x + 1}}{2} = \frac{{y + 2}}{{ – 3}} = \frac{{z – 3}}{4}\)
B. \(\frac{{x – 3}}{1} = \frac{{y + 1}}{2} = \frac{{z – 1}}{{ – 3}}\)
C. \(\frac{{x – 1}}{2} = \frac{{y – 2}}{{ – 3}} = \frac{{z + 3}}{4}\)
D. \(\frac{{x – 1}}{3} = \frac{{y – 2}}{{ – 1}} = \frac{{z + 3}}{1}\)
A. \(\left\{ \begin{array}{l}x = – 2t\\y = 10t\\z = 4t\end{array} \right.;t \in \mathbb{R}\)
B. \(\left\{ \begin{array}{l}x = t – 1\\y = 5\\z = 2\end{array} \right.;t \in \mathbb{R}$ và $\left\{ \begin{array}{l}x = – 2t\\y = 10t\\z = 4t\end{array} \right.;t \in \mathbb{R}\)
C. \(\left\{ \begin{array}{l}x = t – 1\\y = 5\\z = 2\end{array} \right.;t \in \mathbb{R}\)
D. \(\left\{ \begin{array}{l}x = – m\\y = 5m\\z = 2m\end{array} \right.;m \in \mathbb{R}\)
A. \(\,\frac{{x – 1}}{1} = \frac{{y – 2}}{1} = \frac{{z – 4}}{{ – 5}}\)
B. \(\,\frac{{x + 2}}{1} = \frac{{y + 3}}{1} = \frac{{z – 1}}{{ – 5}}\)
C. \(\left\{ \begin{array}{l}x = 2 – t\\y = 3 – t\\z = – 1 + 5t\end{array} \right.\)
D. \(\,\,\left\{ \begin{array}{l}x = 1 – t\\y = 2 – t\\z = 4 + 5t\end{array} \right.\)
A. \(\left\{ {\begin{array}{*{20}{c}}{x = 1 – 2t}\\{y = 2 + 3t}\\{z = – 3 + t}\end{array}} \right.\)
B. \(\left\{ {\begin{array}{*{20}{c}}{x = 1 – 4t}\\{y = 2 – 6t}\\{z = – 3 + 2t}\end{array}} \right.\)
C. \(\left\{ {\begin{array}{*{20}{c}}{x = 1 – 2t}\\{y = 2 + 3t}\\{z = – 3 – t}\end{array}} \right.\)
D. \(\left\{ {\begin{array}{*{20}{c}}{x = – 2 + t}\\{y = 3 + 2t}\\{z = 1 – 3t}\end{array}} \right.\)
A. \(I\left( { – 1;\,2;\, – 3} \right)\)
B. \(I\left( {1;\, – 2;\,3} \right)\)
C. \(I\left( {1;\,2;\,3} \right)\)
D. \(I\left( { – 1;\, – 2;\, – 3} \right)\)
A. \(\sqrt 3\)
B. \(2\sqrt 3\)
C. 2
D. 1
A. \({(x + 1)^2} + {(y – 2)^2} + {z^2} = 4\)
B. \({(x + 1)^2} + {(y – 2)^2} + {z^2} = 16\)
C. \({(x – 1)^2} + {(y + 2)^2} + {z^2} = 16\)
D. \({(x + 1)^2} + {(y – 2)^2} + {z^2} = 4\)
A. \({\left( {x – 1} \right)^2} + {\left( {y + 3} \right)^2} + {\left( {z – 2} \right)^2} = \sqrt {24}\)
B. \({\left( {x + 1} \right)^2} + {\left( {y – 3} \right)^2} + {\left( {z + 2} \right)^2} = \sqrt {24}\)
C. \({\left( {x + 1} \right)^2} + {\left( {y – 3} \right)^2} + {\left( {z + 2} \right)^2} = 24\)
D. \({\left( {x – 1} \right)^2} + {\left( {y + 3} \right)^2} + {\left( {z – 2} \right)^2} = 24\)
A. \({x^2} + {y^2} + {z^2} + 2x + 4y – 4z – 21 = 0\)
B. \(2{x^2} + 2{y^2} + 2{z^2} + 4x + 4y – 8z – 11 = 0\)
C. \({x^2} + {y^2} + {z^2} = 1\)
D. \({x^2} + {y^2} + {z^2} + 2x + 2y – 4z + 11 = 0\)
A. -16
B. 16
C. 4
D. -4
A. \({x^2} + {\left( {y – 2} \right)^2} + {z^2} = 3\)
B. \({(x – 1)^2} + {\left( {y – 2} \right)^2} + {z^2} = 3\)
C. \({(x – 1)^2} + {\left( {y – 2} \right)^2} + {\left( {z + 1} \right)^2} = 9\)
D. \({(x – 1)^2} + {\left( {y – 2} \right)^2} + {z^2} = 9\)
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