Đề thi giữa HK2 môn Toán 12 Trường THPT Nguyễn Chí Thanh năm 2018 - 2019

A. 7

B. - 2

C. 3

D. 8

A. I = 20

B. I = 10

C. I = 40

D. I = 5

A. \(I = \int_1^2 {\sqrt u du} \)

B. \(I = \frac{1}{2}\int_0^3 {\sqrt u du} \)

C. \(I = \frac{1}{2}\int_1^2 {\sqrt u du} \)

D. \(I = \int_0^3 {\sqrt u du} \)

A. 4x+2y - 12z+17 = 0

B. 4x+2y - 12z - 17 = 0

C. - 4x - 2y +12z - 41 = 0

D. - 4x - 2y +12z + 41 = 0

A. (P) : 2x+ y+ z - 3 = 0

B. P :10x - 5y+5z - 3 = 0

C. (P) : 2x - y + z - 7 = 0

D. (P) : 2x + y + z - 5 = 0

A. 2b + a = 0

B. b > a

C. b = a

D. b + 2a = 0

A. I =  m - n 

B. I = - m - n

C. I = n - m

D. I = m + n

A. a - b = 0

B. a + b = 0

C. a + 2b = 0

D. 2a - b = 0

A. \(\frac{1}{{2a}}F\left( {ax + b} \right) + C\)

B. \(aF\left( {ax + b} \right) + C\)

C. \(\frac{1}{{a}}F\left( {ax + b} \right) + C\)

D. \(F\left( {ax + b} \right) + C\)

A. - 1

B. \(\frac{1}{2}\)

C. 0

D. 1

A. 2y - 3z = 0

B. x - 3y = 0

C. 3x + y = 0

D. 2y + 3z = 0

A. \(I = \frac{{11}}{2}\)

B. \(I = \frac{{3}}{2}\)

C. \(I = \frac{{7}}{2}\)

D. \(I = \frac{{5}}{2}\)

A. \(F\left( x \right) = \ln \left| {2x + 5} \right| + 2019\)

B. \(F\left( x \right) =  - \frac{1}{{{{\left( {2x + 5} \right)}^2}}} + 2019\)

C. \(F\left( x \right) =  - \frac{2}{{{{\left( {2x + 5} \right)}^2}}} + 19\)

D. \(F\left( x \right) = \frac{1}{2}\ln \left| {2x + 5} \right| + 2\)

A. G(2;1;1)

B. G(6;3;3)

C. G(2;1;-1)

D. G(1;2;1)

A. 1

B. \(\frac{{\sqrt 2 }}{2}\)

C. \({\sqrt 2 }\)

D. \({\sqrt 3 }\)

A. \( - \frac{3}{2}\)

B. \( - \ln \frac{{\sqrt 2 }}{2}\)

C. \(\ln2\)

D. \(  \ln \frac{{\sqrt 2 }}{2}\)

A. I = 8

B. I = - 12

C. I = - 8

D. I = 12

A. \(\frac{3}{2}\)

B. \(\frac{1}{2}\)

C. \(\frac{1}{3}\)

D. \(\frac{1}{6}\)

A. (0;0;4)

B. (0;0;3)

C. (-1;6;0)

D. (-1;-1;0)

A. \(2{x^2} - 5x + \frac{1}{x} + C\)

B. \({x^2} - 5x + \frac{1}{x} + C\)

C. \(-2{x^2} + 5x - \frac{1}{x} + C\)

D. \(2{x^2} - 5x + \ln \left| x \right| + C\)

A. \(F\left( x \right) = {e^2} + {x^2} + \frac{1}{2}\)

B. \(F\left( x \right) = {e^2} + {x^2} + \frac{5}{2}\)

C. \(F\left( x \right) = {e^2} + {x^2} + \frac{3}{2}\)

D. \(F\left( x \right) = {e^2} + {x^2} - \frac{1}{2}\)

A. \(\int\limits_a^b {f\left( x \right)} dx =  - \int\limits_b^a {f\left( x \right)} dx\)

B. \(\int\limits_a^b {xf\left( x \right)} dx = x\int\limits_a^b {f\left( x \right)} dx\)

C. \(\int\limits_a^b {\left[ {f\left( x \right) + g\left( x \right)} \right]} dx = \int\limits_a^b {f\left( x \right)} dx + \int\limits_a^b {g\left( x \right)} dx\)

D. \(\int\limits_a^b {kf\left( x \right)dx = k\int\limits_a^b {f\left( x \right)dx} \left( {k \in R,k \ne 0} \right)} \)

A. \({\left( {x - 2} \right)^2} + {\left( {y - 1} \right)^2} + {\left( {z + 1} \right)^2} = 1\)

B. \({\left( {x - 2} \right)^2} + {\left( {y - 1} \right)^2} + {\left( {z + 1} \right)^2} = 4\)

C. \({\left( {x + 2} \right)^2} + {\left( {y + 1} \right)^2} + {\left( {z - 1} \right)^2} = 4\)

D. \({\left( {x + 2} \right)^2} + {\left( {y - 1} \right)^2} + {\left( {z + 1} \right)^2} = 2\)

A. 3284 con 

B. 11459 con 

C. 10000 con 

D. 8959 con 

A. \(\frac{x}{a} + \frac{y}{c} + \frac{z}{b} = 1\)

B. \(\frac{x}{b} + \frac{y}{c} + \frac{z}{a} = 1\)

C. \(\frac{x}{a} + \frac{y}{b} + \frac{z}{c} = 1\)

D. \(\frac{x}{c} + \frac{y}{b} + \frac{z}{a} = 1\)

A. S = 1

B. \(S = \frac{1}{2}\)

C. \(S = \frac{3}{8}\)

D. S = 0

A. I(-1;2;-3), R=25

B. I(-1;2;-3), R=5

C. I(1;- 2;3), R=5

D. I(1;- 2;3), R=25

A. 3

B. 1

C. 2

D. \(\frac{1}{2}\)

A. \(\frac{1}{3}{\rm{co}}{{\rm{s}}^3}x + C\)

B. \(\frac{1}{3}{\rm{si}}{{\rm{n}}^3}x + C\)

C. \(\frac{1}{4}{\rm{si}}{{\rm{n}}^4}x + C\)

D. \({\sin ^4}x + C\)

A. 8

B. 14

C. 4

D. 2