A. \( - \frac{5}{3} \le m < 1\)
B. \(1 < m \le \frac{5}{3}\)
C. \(m \le - \frac{5}{3}\)
D. m < 1
A. m < -1
B. m > -1
C. \(m < - \frac{4}{3}\)
D. \(m > \frac{4}{3}\)
A. \(m > \frac{3}{2}\)
B. \(m > \frac{3}{4}\)
C. \(\frac{3}{4} < m < \frac{3}{2}\)
D. \(1 < m < 3\)
A. a= 0
B. a < 0
C. \(0 < a \le \frac{1}{2}\)
D. \(a \ge \frac{1}{2}\)
A. m < 1
B. m > 1
C. \(m < \frac{1}{4}\)
D. \(m > \frac{1}{4}\)
A. \( - 14 < m < 2\)
B. \( - 14 \le m \le 2\)
C. \( - 2 < m < 14\)
D. khác
A. \(\left( { - 2,\frac{{3 - \sqrt {17} }}{2}} \right) \cup \left( {0,2} \right) \cup \left( {\frac{{3 + \sqrt {17} }}{2}, + \infty } \right)\)
B. \(x \notin \left\{ { - 2,0,2} \right\}\)
C. \( - 2 < x < 0\)
D. \(0 < x < 2\)
A. \(S = \left( { - \infty , - 4} \right) \cup \left( { - 1,1} \right) \cup \left( {4, + \infty } \right)\)
B. \(S = \left( { - \infty , - 4} \right)\)
C. \(S = \left( { - 1,1} \right)\)
D. \(S = \left( {4, + \infty } \right)\)
A. 2
B. 3
C. 4
D. 5
A. 0
B. 1
C. 2
D. 3
A. \(\left[ \begin{array}{l} - 7 < x < - 2\\ 3 < x < 4 \end{array} \right.\)
B. \(\left[ \begin{array}{l} - 2 \le x < 1\\ 1 < x < 2 \end{array} \right.\)
C. \(\left[ \begin{array}{l} 0 < x < 3\\ 4 < x < 5 \end{array} \right.\)
D. \(\left[ \begin{array}{l} - 3 < x \le - 2\\ - 1 < x < 1 \end{array} \right.\)
A. \({\left( {a - \frac{b}{2}} \right)^2} + {\left( {a - \frac{c}{2}} \right)^2} + {\left( {a - \frac{d}{2}} \right)^2} + {\left( {a - \frac{e}{2}} \right)^2} \ge 0\)
B. \({\left( {b - \frac{a}{2}} \right)^2} + {\left( {c - \frac{a}{2}} \right)^2} + {\left( {d - \frac{a}{2}} \right)^2} + {\left( {e - \frac{a}{2}} \right)^2} \ge 0\)
C. \({\left( {b + \frac{a}{2}} \right)^2} + {\left( {c + \frac{a}{2}} \right)^2} + {\left( {d + \frac{a}{2}} \right)^2} + {\left( {e + \frac{a}{2}} \right)^2} \ge 0\)
D. \({\left( {a - b} \right)^2} + {\left( {a - c} \right)^2} + {\left( {a - d} \right)^2} + {\left( {a - e} \right)^2} \ge 0\)
Lời giải có ở chi tiết câu hỏi nhé! (click chuột vào câu hỏi).
Copyright © 2021 HOCTAPSGK