Bài toán thể tích kết hợp với bài toán tính khoảng cách từ một điểm đến một mặt phẳng

A $\dpi{100} V_{SABC}= \frac{3a^{3}}{4}$ ; $\dpi{100} d_{B\rightarrow (SAC)}=2a\sqrt{3}$

B $\dpi{100} V_{SABC}= \frac{a^{3}}{4}$ ; $\dpi{100} d_{B\rightarrow (SAC)}=2a\sqrt{3}$

C $\dpi{100} V_{SABC}= \frac{a^{3}}{4}$ ; $\dpi{100} d_{B\rightarrow (SAC)}=a\sqrt{3}$

D $\dpi{100} V_{SABC}= \frac{3a^{3}}{4}$ ; $\dpi{100} d_{B\rightarrow (SAC)}=a\sqrt{3}$

A $\dpi{100} V_{ABCA'B'C'}= a^{3}$ ; $\dpi{100} d_{B'\rightarrow (A'ACC')}$ = $\dpi{100} \frac{2\sqrt{39}a}{13}$

B $\dpi{100} V_{ABCA'B'C'}$ = $\dpi{100} 2a^{3}$ ; $\dpi{100} d_{B'\rightarrow (A'ACC')}$ = $\dpi{100} \frac{2\sqrt{39}a}{13}$

C $\dpi{100} V_{ABCA'B'C'}$ = $\dpi{100} 2a^{3}$ ; $\dpi{100} d_{B'\rightarrow (A'ACC')}$ = $\dpi{100} \frac{\sqrt{39}a}{13}$

D $\dpi{100} V_{ABCA'B'C'}= a^{3}$ ; $\dpi{100} d_{B'\rightarrow (A'ACC')}$ = $\dpi{100} \frac{\sqrt{39}a}{13}$

A $\dpi{100} V_{SABC}= \frac{3a^{3}}{4}$ ; $\dpi{100} d_{B\rightarrow (SAC)}=2a\sqrt{3}$

B $\dpi{100} V_{SABC}= \frac{a^{3}}{4}$ ; $\dpi{100} d_{B\rightarrow (SAC)}=2a\sqrt{3}$

C $\dpi{100} V_{SABC}= \frac{a^{3}}{4}$ ; $\dpi{100} d_{B\rightarrow (SAC)}=a\sqrt{3}$

D $\dpi{100} V_{SABC}= \frac{3a^{3}}{4}$ ; $\dpi{100} d_{B\rightarrow (SAC)}=a\sqrt{3}$

A $\dpi{100} V_{ABCA'B'C'}= a^{3}$ ; $\dpi{100} d_{B'\rightarrow (A'ACC')}$ = $\dpi{100} \frac{2\sqrt{39}a}{13}$

B $\dpi{100} V_{ABCA'B'C'}$ = $\dpi{100} 2a^{3}$ ; $\dpi{100} d_{B'\rightarrow (A'ACC')}$ = $\dpi{100} \frac{2\sqrt{39}a}{13}$

C $\dpi{100} V_{ABCA'B'C'}$ = $\dpi{100} 2a^{3}$ ; $\dpi{100} d_{B'\rightarrow (A'ACC')}$ = $\dpi{100} \frac{\sqrt{39}a}{13}$

D $\dpi{100} V_{ABCA'B'C'}= a^{3}$ ; $\dpi{100} d_{B'\rightarrow (A'ACC')}$ = $\dpi{100} \frac{\sqrt{39}a}{13}$

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Toán học - Lớp 12