$\rm PTHH: 2CH_3COOH +Zn  \xrightarrow{} (CH_3COO)_2Zn +H_2$ 

$\rm n_{(CH_3COO)_2Zn}=\dfrac{1,83}{183}=0,01(mol)$ 

theo pthh 

$n_{CH_3COOH}=2n_{(CH_3COO)_2Zn}=0,02(mol)$ 

`->`$\rm C_{M_{CH_3COOH}}=\dfrac{0,02}{0,04}=0,5M$ 

`b)` 

theo pthh 

$n_{H_2}=n_{(CH_3COO)_2Zn}=0,01(mol)$ 

`->`$V_{H_2}=0,01.22,4 =0, 224(l)$ 

`c)` 

$\rm PTHH: CH_3COOH +NaOH \xrightarrow{} CH_3COONa +H_2O$ 

theo pthh 

$n_{NaOH}=n_{CH_3COOH}=0,02(mol)$ 

`->`$V_{NaOH}=\dfrac{0,02}{0,75}= \dfrac{2}{75}(l)$ 

Đáp án`+`Giải thích các bước giải:

`a)` `PTHH: 2CH_3COOH +Zn  \rightarrow (CH_3COO)_2Zn +H_2``(1)`

` n_{(CH_3COO)_2Zn}=\frac{1,83}{183}=0,01(mol)`

Theo `PTHH(1):` `n_{CH_3COOH}=2n_{(CH_3COO)_2Zn}=0,02(mol)`

`=>`` C_{M_{CH_3COOH}}=\frac{0,02}{0,04}=0,5(M)`

`b)` Theo `PTHH(1):` `n_{H_2}=n_{(CH_3COO)_2Zn}=0,01(mol)` 

`=>``V_{H_2}=0,01.22,4 =0, 224(l)` 

`c)` `PTHH: CH_3COOH +NaOH \rightarrow CH_3COONa +H_2O``(2)`

Theo `PTHH(2):``n_{NaOH}=n_{CH_3COOH}=0,02(mol)`

`=>``V_{NaOH}=\frac{0,02}{0,75}= \frac{2}{75}(l)`