Đáp án+Giải thích các bước giải:

Bài 7 

`a.`

$(1)2Fe+3Cl_{2}\xrightarrow[]{t^{o}}2FeCl_{3}$

$(2)FeCl_{3}+3NaOH→Fe(OH)_{3}+3NaCl$

$(3)2Fe(OH)_{3}+3H_{2}SO_{4}→Fe_{2}(SO_{4})_{3}+6H_{2}O$

$(4)Fe_{2}(SO_{4})_{3}+3BaCl_{2}→3BaSO_{4}+2FeCl_{3}$

`b.`

$(1)Fe(NO_{3})_{3}+3NaOH→Fe(OH)_{3}+3NaNO_{3}$

$(2)2Fe(OH)_{3}\xrightarrow[]{t^{o}}Fe_{2}O_{3}+3H_{2}O$

$(3)Fe_{2}O_{3}+3CO\xrightarrow[]{t^{o}}2Fe+3CO_{2}$

$(4)Fe+2HCl→FeCl_{2}+H_{2}$

$(5)FeCl_{2}+2NaOH→2NaCl+Fe(OH)_{2}$

Bài 8

`Al→Al_{2}O_{3}→AlCl_{3}→Al(OH)_{3}`

$(1)4Al+3O_{2}\xrightarrow[]{t^{o}}3Al_{2}O_{3}$

$(2)Al_{2}O_{3}+6HCl→2AlCl_{3}+3H_{2}O$

$(3)AlCl_{3}+3NaOH→3NaCl+Al(OH)_{3}$

bài 7:

`a.(1)2Fe+3Cl_2 \overset(t^o)(->)2FeCl_3`

`(2)FeCl_3+3KOH->Fe(OH)_3+3KCl`

`(3)2Fe(OH)_3+3H_2SO_4->Fe_2(SO_4)_3+6H_2O`

`(4)Fe_2(SO_4)_3+3BaCl_2->2FeCl_3+3BaSO_4`

`b.`

`(1)Fe(NO_3)_3+3NaOH->Fe(OH)_3+3NaNO_3`

`(2)2Fe(OH)_3 \overset(t^o)(->)Fe_2O_3+3H_2O`

`(3)Fe_2O_3+3CO \overset(t^o)(->)2Fe+3CO_2`

`(4)Fe+2HCl->FeCl_2+H_2`

`(5)FeCl_2+2NaOH->Fe(OH)_2+2NaCl`

bài 8:

`Al->AlCl_3->Al(OH)_3->Al_2O_3`

`4Al+3O_2 \overset(t^o)(->)2Al_2O_3`

`AlCl_3+3NaOH->Al(OH)_3+3NaCl`

`2Al(OH)_3 \overset(t^o)(->)Al_2O_3+3H_2O`

`-`  `Al(OH)_3->Al_2O_3->AlCl_3->Al`

`2Al(OH)_3 \overset(t^o)(->)Al_2O_3+3H_2O`

`Al_2O_3+6HCl->2AlCl_3+3H_2O`

`3Mg+2AlCl_3->3MgCl_2+2Al`