`@`PTHH:

$\rm 6CO_2+6H_2O \xrightarrow{\text{quang hợp}}C_6H_{12}O_6+6O_2$

`@` `n_{CO_2}=(88)/(44)=2(\text{tấn mol})`

`=>n_{O_2}=n_{CO_2}=2(\text{tấn mol})` hay `2.10^{6}(mol)`

`n_{C_6H_{12}O_6}= 1/6 n_{CO_2}= 1/6 . 2.10^{6}=1/3 .10^{6}(mol)`

`=>V_{O_2}=2.10^{6}.24,79=49,58.10^{6}(\text{lít})`

`m_{C_6H_{12}O_6}=1/3 . 10^{6} . 180=6.10^{7}(g)`

`6CO_2 + 6H_2O \overset(quang hợp)(->) C_6H_{12}O_6 + 6O_2`

`n_{CO_2} = {88}/{44} = 2(tấn mol) = 2 . 10^6(mol)`

`n_{C_6H_{12}O_6} = 1/6n_{CO_2} = {2 . 10^6}/6 = 1/3 . 10^6`( mol)

`n_{O_2} = n_{CO_2} = 2 . 10^6 (mol)`

`m_{C_{6}H_{12}O_{6}} = 1/3 . 10^6 . 180 = 60 . 10^6(g)`

`V_{O_2} = 2 . 10^6 . 24,79 = 49,58. 10^6(l)`