`n_{HI}={90,4}/{128}=0,70625(mol)`

`n_{H_2\ bd}={0,763}/2=0,3815(mol)`

`n_{I_2\ bd}={96,9}/{254}=0,3815(mol)`

`C_{H_2\ bd}=C_{I_2\ bd}={0,3815}/{3,67}=0,104\ M`

`[HI]={0,70625}/{3,67}=0,192M`

`H_2(g)+I_2(g)`  $\rightleftharpoons$  `2HI(g)`

BD: `0,104`    `0,104(M)`

PU: `0,096`    `0,096`     `0,192(M)`

CB: `0,008`     `0,008`    `0,192(M)`

`->K_C={[HI]^2}/{[I_2].[H_2]}={0,192^2}/{0,008.0,008}=576`