`n_{Br_2}=0,2.1=0,2(mol)`

`PTHH:C_2H_4+Br_2->C_2H_4Br_2`

`CTCT: CH_2Br-CH_2Br`

`n_{C_2H_4Br_2}=n_{Br_2}=0,2(mol)`

`=>m_{C_2H_4Br_2}=0,2.188=37,6(g)`

`n_{C_2H_4}=n_{Br_2}=0,2(mol)`

`=>V_{C_2H_4}=0,2.22,4=4,48(l)`

`%V_{C_2H_4}={4,48}/{11,2}.100%=40%`

`%V_{CH_4}=100-40=60%`

`200` `ml` `=` `0,2` `l`

`a)` $\text{Chỉ có}$ $etilen$ $pứ$ $\text{với dd}$ $brom$

`C_2H_4` `+` `Br_2` `->` `C_2H_4Br_2`

$CTCT:$ $Br-H_2C-CH_2-Br$

`b)` `n_(C_2H_4Br_2` `=` `0,2` `.` `1` `=` `0,2` `(mol)`

`m_(C_2H_4Br_2` `=` `188` `.` `0,2` `=` `37,6` `(g)`

`c)` `n_(C_2H_4` `=` `n_(C_2H_4Br_2` `=` `0,2` `(mol)`

`V_(C_2H_4` `=` `22,4` `.` `0,2` `=` `4,48` $\text{(lít)}$

`%V_(C_2H_4` `=` `4,48` `:` `11,2` `=` `40%`

`%V_(CH_4` `=` `100%` `-` `40%` `=` `60%`

`#TranDucQuangNBK`