`c)`

`C_2H_4+ H_2O`$\xrightarrow{180°C, H_2SO_4}$`C_2H_5OH`

`C_2H_5OH+ O_2`$\xrightarrow{men,t°}$`CH_3COOH + H_2O`

`2CH_3COOH + Zn→(CH_3COO)_2Zn+ H_2`

`CH_3COOH + C_2H_5OH`$\buildrel{{H_2SO_4,t°}}\over\rightleftharpoons$`CH_3COOC_2H_5+ H_2O`

`d)`

`C_6H_12O_6`$\xrightarrow{t°,men}$`2C_2H_5OH + 2CO_2`

`CH_3COOH + C_2H_5OH`$\buildrel{{H_2SO_4,t°}}\over\rightleftharpoons$`CH_3COOC_2H_5+ H_2O`

`CH_3COOC_2H_5+ NaOH`$\xrightarrow{t°}$`CH_3COONa+ C_2H_5OH`

`e)`

`CH_3COOH+ 2O_2`$\xrightarrow{t°}$`2CO_2 + 2H_2O`

`CH_3COOH + Na→ CH_3COONa+1/2H_2`

`2CH_3COOH + CuO →(CH_3COO)_2Cu + H_2O`

`CH_3COOH + NaOH→ CH_3COONa + H_2O`

`CH_3COOH + C_2H_5OH`$\buildrel{{H_2SO_4,t°}}\over\rightleftharpoons$`CH_3COOC_2H_5+ H_2O`

`2CH_3COOH + Na_2CO_3→ 2CH_3COONa + CO_2+ H_2O`

Đáp án:

Giải thích các bước giải:

 `c)`

`C_2H_5 +H_2O overset(t^o,xt)(->) C_2H_5OH `

`C_2H_5OH + O_2  oversetenzim(->) CH_3COOH + H_2O`

`2CH_3COOH + Zn -> (CH_3COO)_2Zn + H_2`

`CH_3COOH + C_2H_5OH ` $\buildrel{{t^o,xt}}\over\rightleftharpoons$ `CH_3COOC_2H_5 + H_2O`

`d)` 

`C_6H_(12)O_6`  $\xrightarrow{\text{lên men}}$ `2C_2H_5OH + 2CO_2`

`CH_3COOH + C_2H_5OH ` $\buildrel{{t^o,xt}}\over\rightleftharpoons$ `CH_3COOC_2H_5 + H_2O` 

`CH_3COOC_2H_5+ NaOH -> CH_3COONa + C_2H_5OH `

`e)`

Phản ứng cháy : 

`CH_3COOH +2 O_2 `$\xrightarrow{t^o}$ `2CO_2 + 2H_2O`

Phản ứng tác dụng kim loại :
`2CH_3COOH + Zn -> (CH_3COO)_2Zn  +H_2 

Phản ứng tác dụng base

`CH_3COOH + NaOH -> CH_3COONa + H_2O`

Phản ứng tác dụng với rượu : 

`CH_3COOH + C_2H_5OH ` $\buildrel{{t^o,xt}}\over\rightleftharpoons$ `CH_3COOC_2H_5 + H_2O`

Phản ứng tác dụng muối :

`2CH_3COOH + Na_2SO_3 -> 2CH_3COONa + H_2O + SO_2`

Phản ứng tác dụng với oxide

`2CH_3COOH + MgO -> (CH_3COO)_2Mg + H_2O`