`a)`

`C_2H_4 + H_2O`$\xrightarrow{H_2SO_4,t°}$`C_2H_5OH`

`C_2H_5OH + O_2`$\xrightarrow{men,t°}$`CH_3COOH + H_2O`

`CH_3COOH + C_2H_5OH`$\buildrel{{H_2SO_4,t°}}\over\rightleftharpoons$`CH_3COOC_2H_5+ H_2O`

`CH_3COOC_2H_5+ NaOH`$\xrightarrow{t°}$`CH_3COONa+ C_2H_5OH`

`b)`

`C_6H_{12}O_6`$\xrightarrow{men,t°}$`2C_2H_5OH + 2CO_2`

`C_2H_5OH + O_2`$\xrightarrow{men,t°}$`CH_3COOH + H_2O`

`CH_3COOH + C_2H_5OH`$\buildrel{{H_2SO_4,t°}}\over\rightleftharpoons$`CH_3COOC_2H_5+ H_2O`

`CH_3COOH + Na→ CH_3COONa + 1/2H_2`

Đáp án:

Giải thích các bước giải:

 `a)`

`C_2H_4 + H_2O   overset(t^o,xt)(->)  C_2H_5OH `

`C_2H_5OH + O_2  overset(t^o,xt)(->)  CH_3COOH + H_2O`

`CH_3COOH + C_2H_5OH ` $\buildrel{{t^o,xt}}\over\rightleftharpoons$ `CH_3COOC_2H_5 + H_2O` 

`CH_3COOC_2H_5 + NaOH -> CH_3COONa + H_2O

`b)`

`C_6H_(12)O_6`  $\xrightarrow{\text{lên men}}$ `2C_2H_5OH + 2CO_2`

`C_2H_5OH + O_2  overset(t^o,xt)(->)  CH_3COOH + H_2O`

`CH_3COOH + C_2H_5OH ` $\buildrel{{t^o,xt}}\over\rightleftharpoons$ `CH_3COOC_2H_5 + H_2O` `CH_3COOC_2H_5 + NaOH -> CH_3COONa + H_2O