Đáp án:

$C_{12}H_{22}O_{11}+H_2O\xrightarrow{{H_2SO_4, t^o}} C_6H_{12}O_6+C_6H_{12}O_6$ 

$C_6H_{12}O_6\xrightarrow{{\text{men rượu}, 30-35^oC}} 2CO_2+2C_2H_5OH$ 

$C_2H_5OH+O_2\xrightarrow{{\text{men giấm}}} CH_3COOH+H_2O$ 

$CH_3COOH+NaOH\to CH_3COONa+H_2O$

$CH_3COOH+C_2H_5OH\buildrel{{H_2SO_4 đ, t^o}}\over\rightleftharpoons CH_3COOC_2H_5+H_2O$ 

$CH_3COOC_2H_5+NaOH\xrightarrow{{t^o}} CH_3COONa+C_2H_5OH$