Đáp án:

1)

a, $CaC_2+2H_2O\to Ca(OH)_2+C_2H_2$ 

b, $C_2H_4+H_2O\xrightarrow{{H_2SO_4, t^o}} C_2H_5OH$ 

c, $C_2H_2+H_2\xrightarrow{{Pd, PbCO_3, t^o}} C_2H_4$ 

d, $C_2H_6O+3O_2\xrightarrow{{t^o}} 2CO_2+3H_2O$ 

2)

$C_{12}H_{22}O_{11}+H_2O\xrightarrow{{H^+, t^o}} C_6H_{12}O_6+C_6H_{12}O_6$ 

$C_6H_{12}O_6\xrightarrow{{\text{men rượu}, 30-35^oC}} 2CO_2+2C_2H_5OH$ 

$C_2H_5OH+O_2\xrightarrow{{\text{men giấm}}} CH_3COOH+H_2O$ 

$CH_3COOH+C_2H_5OH\buildrel{{H_2SO_4 đ, t^o}}\over\rightleftharpoons CH_3COOC_2H_5+H_2O$

1)

$\rm a)CaC_2 + 2H_2O \to Ca(OH)_2 + C_2H_2$

$\rm b)C_2H_4 + H_2O \xrightarrow[Axit]{t^o} C_2H_5OH$

$\rm c)C_2H_2 + H_2 \xrightarrow[Pd]{t^o} C_2H_4$

$\rm d)C_2H_6O + 3O_2 \xrightarrow[]{t^o} 2CO_2 + 3H_2O$

________________________________

2)

$\rm 1)C_{12}H_{22}O_{11} + H_2O \xrightarrow[Axit]{t^o} C_6H_{12}O_6 + C_6H_{12}O_6$

$\rm 2)C_6H_{12}O_6 \xrightarrow[30-35^oC]{\text{men rượu}} 2C_2H_5OH + 2CO_2$

$\rm 3)C_2H_5OH + O_2 \xrightarrow[]{\text{men giấm}} CH_3COOH + H_2O$

$\rm 4)CH_3COOH+C_2H_5OH \rm \overset{t^°,\ H_2SO_4 đặc}\leftrightarrows CH_3COOC_2H_5 + H_2O$