Đáp án:

$\rm a)\\2C_4H_{10}+5O_2\xrightarrow{Mn^{2+},\ t^°}4CH_3COOH+2H_2O\\CH_3COOH+C_2H_5OH\overset{H_2SO_4\ (dac),\ t^°}\leftrightarrows CH_3COOC_2H_5+H_2O\\CH_3COOC_2H_5+NaOH\xrightarrow{t^°}CH_3COONa+C_2H_5OH\\C_2H_5OH+Na\to C_2H_5ONa+\dfrac{1}{2}H_2\\b)\\C_2H_4+H_2O\xrightarrow{H_2SO_4\ (dac),\ t^°}C_2H_5OH\\C_2H_5OH+O_2\xrightarrow{men,\ t^°}CH_3COOH+H_2O$

H+2H2O2𝐶4𝐻10+5𝑂2𝑡𝑜→4𝐶𝐻3𝐶𝑂𝑂𝐻+2𝐻2𝑂

CH3COOH+C2H5OHto−−−−−−→H2SO4đặcCH3COOC2H5+H2O𝐶𝐻3𝐶𝑂𝑂𝐻+𝐶2𝐻5𝑂𝐻→𝐻2𝑆𝑂4đặ𝑐𝑡𝑜𝐶𝐻3𝐶𝑂𝑂𝐶2𝐻5+𝐻2𝑂

CH3COOC2H5 + NaOH →→ CH3COONa + C2H5OH

C2H5OH+3O2to→2CO2+3H2O

CaC2 + 2H2O→→ C2H2 + Ca(OH)2

C2H2+H2to→C2H4𝐶2𝐻2+𝐻2𝑡𝑜→𝐶2𝐻4

C2H4+H2Oaxit−−→C2H5OH𝐶2𝐻4+𝐻2𝑂𝑎𝑥𝑖𝑡→𝐶2𝐻5𝑂𝐻

C2H5OH+3O2to→2CO2+3H2O𝐶2𝐻5𝑂𝐻+3𝑂2𝑡𝑜→2𝐶𝑂2+3𝐻2𝑂

CO2 + 2NaOH →→ Na2CO3 + H2O

2CH3COOH + Na2CO3 →→ 2CH3COONa + CO2 + H2O10:14/-strong/-heart:>:o:-((:-hĐã gửiXem trước khi gửiThả Files vào đây để xem lại trước khi gửi