Đáp án:

 a/

$CaC_{2} +2H_{2}O → C_{2}H_{2} +Ca(OH)_{2}$

$C_{2}H_{2}+ Br_{2} → C_{2}H_{2}Br_{2}$

$C_{2}H_{2}Br_{2} +Br_{2} → C_{2}H_{2}Br_{4}$

$C_{2}H_{2} +H_{2} \buildrel{{Pd/PbCO_{3},t^o}}\over\longrightarrow C_{2}H_{4}$

$CH_{2}=CH_{2} \buildrel{{t^o,xt,P}}\over\longrightarrow -[CH_{2}-CH_{2}]-_{n} (PE)$

$C_{2}H_{4} +Br_{2} → C_{2}H_{4}Br_{2}$

b/

$CH_{3}COONa+ NaOH \buildrel{{CaO,t^o}}\over\longrightarrow CH_{4} + Na_{2}CO_{3}$

$CH_{4} +Cl_{2} \buildrel{{as}}\over\longrightarrow CH_{3}C + HCll$

$CH_{3}Cl + Cl_{2}  \buildrel{{as}}\over\longrightarrow CH_{2}Cl_{2} + HCl$

c/

$CaC_{2} +2H_{2}O → C_{2}H_{2} + Ca(OH)_{2}$

$C_{2}H_{2} + H_{2} \buildrel{{Pd/PbCO_{3}, t^o}}\over\longrightarrow C_{2}H_{4}$

$C_{2}H_{4} +H_{2}O → C_{2}H_{5}OH$

$C_{2}H_{5}OH \buildrel{{H_{2}SO_{4}đ,170^oC}}\over\longrightarrow C_{2}H_{4} +H_{2}O$

$C_{2}H_{4} +Br_{2} → C_{2}H_{4}Br_{2}$

d/

$2CH_{4} \buildrel{{1500^oC,làm lạnh nhanh}}\over\longrightarrow C_{2}H_{2} +3H_{2}$

$C_{2}H_{2} + H_{2} \buildrel{{Pd/PbCO_{3}, t^o}}\over\longrightarrow C_{2}H_{4}$

$C_{2}H_{4} + H_{2} \buildrel{{Ni, t^o}}\over\longrightarrow C_{2}H_{6}$

$C_{2}H_{6}+ Cl_{2} \buildrel{{ as}}\over\longrightarrow C_{2}H_{5}Cl+ HCl$

$C_{2}H_{2}+ Br_{2} → C_{2}H_{2}Br_{2}$

$C_{2}H_{2}Br_{2} → C_{2}H_{4}Br_{2}$ Cái này mình không rõ lắm 

e/

$C_{2}H_{2}+ Br_{2} → C_{2}H_{2}Br_{2}$

$C_{2}H_{2} + H_{2} \buildrel{{Pd/PbCO_{3}, t^o}}\over\longrightarrow C_{2}H_{4}$

$C_{2}H_{4}+ Br_{2} → C_{2}H_{4}Br_{2}$

$C_{2}H_{4} + H_{2} \buildrel{{Ni, t^o}}\over\longrightarrow C_{2}H_{6}$

$C_{2}H_{6} +7/2O_{2}  \buildrel{{ t^o}}\over\longrightarrow 2CO_{2} +3H_{2}O$

f/

$2CH_{4} \buildrel{{1500^oC,làm lạnh nhanh}}\over\longrightarrow C_{2}H_{2} +3H_{2}$

$C_{2}H_{2} + H_{2} \buildrel{{Pd/PbCO_{3}, t^o}}\over\longrightarrow C_{2}H_{4}$

$C_{2}H_{4} +HCl \buildrel{{ t^o}}\over\longrightarrow C_{2}H_{5}Cl $

$CH_{2}=CH_{2} \buildrel{{t^o,xt,P}}\over\longrightarrow -[CH_{2}-CH_{2}]-_{n} (PE)$

$C_{2}H_{4} → C_{2}H_{2}Br_{2}$ cái này mình không rõ lắm

Giải thích các bước giải:

Đáp án:

Giải thích các bước giải:

 d, 2CH4-->C2H2+3H2

     C2H2+H2-->C2H4

     C2H4+H2-->C2H6

     2C2H6+Cl2-->2C2H5Cl+H2

     C2H2+Br2-->C2H2Br2

     C2H2Br2+H2-->C2H4Br2

e,C2H2+H2-->C2H4

   C2H4+H2-->C2H6

   2C2H6+7O2-->6H2O+4CO2

   C2H2+Br2-->C2H2Br2

    C2H4+Br2-->C2H2Br2+H2

f, 2CH4-->C2H2+3H2

   C2H2+H2-->C2H4

   C2H4+Br2-->C2H2Br2+H2

    C2H2Br2+H2-->C2H2Br2+H2

   chúc bạn học tốt!