Em tham khảo nha:

\(\begin{array}{l}
a)\\
{C_x}{H_y}{O_z} + \frac{{2x + y - z}}{2}{O_2} \to xC{O_2} + y{H_2}O\\
b)\\
4X + 5{Y_2} \to 2{X_2}{Y_5}\\
c)\\
5R + 12HN{O_3} \to 5R{(N{O_3})_2} + {N_2} + 6{H_2}O\\
d)\\
{R_x}{O_y} + yCO \to xR + yC{O_2}\\
e)\\
3{R_x}{O_y} + (12x - 2y)HN{O_3} \to 3xR{(N{O_3})_3} + (3x - 2y)NO + (6x - y){H_2}O\\
\end{array}\)

$a,_{}$ $C_{x}$$H_{y}$$O_{Z}$ + $\frac{2x + y -2}{2}$ $O_{2}$ $\frac{t^{o}}{}$> $xCO_{2}$ + $yH_{2}O$

$b,_{}$ $4X_{}$ + $5Y_{2}$ → $2X_{2}$$Y_{5}$

$c,_{}$ $5R_{}$ + $12HNO_{3}$ → $5R(NO_{3}$$)_{2}$ + $N_{2}$ + $6H_{2}O$ 

$d,_{}$ $R_{x}$$O_{y}$ + $yCO_{123}$ → $xR_{}$ + $yCO_{2}$

$e,_{}$ $3R_{x}$$O_{y}$ + $(12x-2y)HNO_{3}$ → $3xR(NO_{3}$$)_{3}$ + $(3x-2y)NO_{}$ + $(6x-y)H_{2}O$ 

Mong bn cho mik ctlhn nhé!! @

UwU