1.`2Al+3H_2SO_4→Al_2(SO4)_3+3H_2`

2.`2Al+6HCl→2AlCl_3+3H_2`

3.`Fe+2HCl→FeCl_2+H_2`

4.`Fe+H_2SO_4→FeSO_4+H_2`

5.`Mg+H_2SO_4→MgSO_4+H_2`

6.`Mg+2HCl→MgCl_2+H_2`

7.`Zn+2HCl→ZnCl_2+H_2`

8.`Zn+H_2SO_4→ZnSO_4+H_2`

9.`Ba+H_2SO_4→BaSO_4↓+H_2`

10.`Ba+2HCl→BaCl_2+H_2`

11.`2Na+2H_2O→2NaOH+H_2`

12.`2K+2H_2O→2KOH+H_2`

13.`Ba+2H_2O→Ba(OH)_2+H_2`

14.`Ca+2H_2O→Ca(OH)_2+H_2`

15.`Fe+H_2O→X`

16.`Na_2O+H_2O→2NaOH`

17.`K_2O+H_2O→2KOH`

18.`BaO+H_2O→Ba(OH)_2`

19.`CaO+H_2O→Ca(OH)_2`

20.`FeO+2HCl→FeCl_2+H_2O`

21.`Fe_2O_3+6HCl→2FeCl_3+3H_2O`

22.`Al_2O_3+6HCl→2AlCl_3+3H_2O`

23.`CuO+2HCl→CuCl_2+H_2O`

24.`ZnO+2HCl→ZnCl_2+H_2O`

25.`Fe_3O_4+8HCl→FeCl_2+2FeCl_3+4H_2O`

26.`BaO+H_2SO_4→BaSO_4↓+H_2O`

27.`NaOH+HCl→NaCl+H_2O`

28.`Ba(OH)_2+H_2SO_4→BaSO_4↓+2H_2O`

29.`CuCl_2+2NaOH→Cu(OH)_2↓+2NaCl`

30.`KOH+HNO_3→KNO_3+H_2O`

Em tham khảo nha:

\(\begin{array}{l}
1)\,2Al + 3{H_2}S{O_4} \to A{l_2}{(S{O_4})_3} + 3{H_2}\\
2)\,2Al + 6HCl \to 2AlC{l_3} + 3{H_2}\\
3)\,Fe + 2HCl \to FeC{l_2} + {H_2}\\
4)\,Fe + {H_2}S{O_4} \to FeS{O_4} + {H_2}\\
5)\,Mg + {H_2}S{O_4} \to MgS{O_4} + {H_2}\\
6)\,Mg + 2HCl \to MgC{l_2} + {H_2}\\
7)\,Zn + 2HCl \to ZnC{l_2} + {H_2}\\
8)\,Zn + {H_2}S{O_4} \to ZnS{O_4} + {H_2}\\
9)\,Ba + {H_2}S{O_4} \to BaS{O_4} + {H_2}\\
10)\,Ba + 2HCl \to BaC{l_2} + {H_2}\\
11)\,2Na + 2{H_2}O \to 2NaOH + {H_2}\\
12)\,2K + 2{H_2}O \to 2KOH + {H_2}\\
13)\,Ba + 2{H_2}O \to Ba{(OH)_2} + {H_2}\\
14)\,Ca + 2{H_2}O \to Ca{(OH)_2} + {H_2}\\
15)\, \text{ Không xảy ra phản ứng }\\
16)\,N{a_2}O + {H_2}O \to 2NaOH\\
17)\,{K_2}O + {H_2}O \to 2KOH\\
18)\,BaO + {H_2}O \to Ba{(OH)_2}\\
19)\,CaO + {H_2}O \to Ca{(OH)_2}\\
20)\,FeO + 2HCl \to FeC{l_2} + {H_2}O\\
21)\,F{e_2}{O_3} + 6HCl \to 2FeC{l_3} + 3{H_2}O\\
22)\,A{l_2}{O_3} + 6HCl \to 2AlC{l_3} + 3{H_2}O\\
23)\,CuO + 2HCl \to CuC{l_2} + {H_2}O\\
24)\,ZnO + 2HCl \to ZnC{l_2} + {H_2}O\\
25)\,F{e_3}{O_4} + 8HCl \to 2FeC{l_3} + FeC{l_2} + 4{H_2}O\\
26)\,BaO + {H_2}S{O_4} \to BaS{O_4} + {H_2}O\\
27)\,NaOH + HCl \to NaCl + {H_2}O\\
28)\,Ba{(OH)_2} + {H_2}S{O_4} \to BaS{O_4} + 2{H_2}O\\
29)\,CuC{l_2} + 2NaOH \to Cu{(OH)_2} + 2NaCl\\
30)\,KOH + HN{O_3} \to KN{O_3} + {H_2}O
\end{array}\)