Đáp án:

\(\% {m_{Zn}} = 44,5\% ;\% {m_{ZnO}} = 55,5\% \)

\({m_{ZnC{l_2}}}  = 27,2{\text{ gam}}\)

\({m_{dd{\text{ HCl}}}} = 40,56{\text{ gam}}\)

Giải thích các bước giải:

Phản ứng xảy ra:

\(Zn + 2HCl\xrightarrow{{}}ZnC{l_2} + {H_2}\)

\(ZnO + 2HCl\xrightarrow{{}}ZnC{l_2} + {H_2}O\)

Ta có:

\({n_{{H_2}}} = \frac{{2,24}}{{22,4}} = 0,1{\text{ mol = }}{{\text{n}}_{Zn}}\)

\( \to {m_{Zn}} = 0,1.65 = 6,5{\text{ }}gam \to {m_{ZnO}} = 14,6 - 6,5 = 8,1{\text{ gam}}\)

\( \to {n_{ZnO}} = \frac{{8,1}}{{65 + 16}} = 0,1{\text{ mol}}\)

Ta có:

\(\% {m_{Zn}} = \frac{{6,5}}{{14,6}} = 44,5\%  \to \% {m_{ZnO}} = 55,5\% \)

\({n_{ZnC{l_2}}} = {n_{Zn}} + {n_{ZnO}} = 0,2{\text{ mol}}\)

\( \to {m_{ZnC{l_2}}} = 0,2.(65 + 35,5.2) = 27,2{\text{ gam}}\)

\({n_{HCl}} = 2{n_{ZnC{l_2}}} = 0,4{\text{ mol}}\)

\( \to {m_{HCl}} = 0,4.36,5 = 14,6{\text{ gam}}\)

\( \to {m_{dd{\text{ HCl}}}} = \frac{{14,6}}{{36\% }} = 40,56{\text{ gam}}\)