Em tham khảo nha:

\(\begin{array}{l}
a)\\
{C_3}{H_4} + 4{O_2} \xrightarrow{t^0} 3C{O_2} + 2{H_2}O\\
2{C_3}{H_6} + 9{O_2} \xrightarrow{t^0} 6C{O_2} + 6{H_2}O\\
{C_3}{H_8} + 5{O_2} \xrightarrow{t^0} 3C{O_2} + 4{H_2}O\\
C{O_2} + Ca{(OH)_2} \xrightarrow{t^0} CaC{O_3} + {H_2}O\\
b)\\
{n_{CaC{O_3}}} = \dfrac{{30}}{{100}} = 0,3\,mol\\
{n_{C{O_2}}} = {n_{CaC{O_3}}} = 0,3\,mol\\
{V_{C{O_2}}} = 0,3 \times 22,4 = 6,72l\\
{M_{hh}} = 22 \times 2 = 44g/mol\\
{n_{hh}} = \dfrac{{2,24}}{{22,4}} = 0,1\,mol\\
{m_{hh}} = 0,1 \times 44 = 4,4g\\
{n_C} = {n_{C{O_2}}} = 0,3\,mol\\
{m_H} = 4,4 - 0,3 \times 12 = 0,8g\\
{n_H} = \dfrac{{0,8}}{2} = 0,4\,mol \Leftrightarrow {n_{{H_2}O}} = \dfrac{{0,4}}{2} = 0,2\,mol\\
{m_{{H_2}O}} = 0,2 \times 18 = 3,6g
\end{array}\)