⊕CaO:

%${M_{Ca}}$=$\frac{40}{40+16}$.100≈71,42 %

%${M_{O}}$=100%-71,42=28,58 %

⊕SO2:

%${M_{S}}$=$\frac{32}{32+16.2}$.100=50 %

%${M_{O}}$=100 %-50 %=50 %

⊕P2O5:

%${M_{P}}$=$\frac{31.2}{31.2+16.5}$.100≈43,66 %

%${M_{O}}$=100 %-43,66 %=56,34 %

⊕NO:

%${M_{N}}$=$\frac{14}{14+16}$.100≈46,67 %

%${M_{O}}$=100 %-46,67 %=53,33 %

⊕K2O:

%${M_{K}}$=$\frac{39.2}{39.2+16}$.100≈83 %

%${M_{O}}$=100%-83 %=17 %

------------------------Nguyễn Hoạt------------------------

Đáp án:

Giải thích các bước giải:

 `M_{CaO}=56\ (đvC)`

`%m_{Ca}=\frac{40}{56}.100% \approx 71,43%`

`%m_{O}=\frac{16}{56}.100% \approx 28,57%`

`M_{SO_2}=32+32=64\ (đvC)`

`%m_{S}=\frac{32}{64}.100% =50%`

`%m_{O}=\frac{32}{64}.100% =50%`

`M_{P_2O_5}=31.2+16.5=142\ (đvC)`

`%m_{P}=\frac{62}{145}.100% \approx 42,76%`

`%m_{O}=\frac{80}{145}.100% \approx 55,17%`

`M_{NO}=14+16=30\ (đvC)`

`%m_{N}=\frac{14}{30}.100% \approx 46,67%`

`%m_{O}=\frac{16}{30}.100% \approx 53,33%`

`M_{K_2O}=39.2+16=94\ (đvC)`

`%m_{K}=\frac{78}{94}.100% \approx 82,98%`

`%m_{O}=\frac{16}{94}.100% \approx 17,02%`