Em tham khảo nha:

\(\begin{array}{l}
a)\\
Mg + 2HCl \to MgC{l_2} + {H_2}\\
MgO + 2HCl \to MgC{l_2} + {H_2}O\\
b)\\
{n_{{H_2}}} = \dfrac{{3,36}}{{22,4}} = 0,15\,mol\\
{n_{Mg}} = {n_{{H_2}}} = 0,15\,mol\\
{m_{Mg}} = 0,15 \times 24 = 3,6g\\
{m_{MgO}} = 10 - 3,6 = 6,4g\\
c)\\
\% {m_{Mg}} = \dfrac{{3,6}}{{10}} \times 100\%  = 36\% \\
\% {m_{MgO}} = 100 - 36 = 64\% \\
d)\\
{n_{MgO}} = \dfrac{{6,4}}{{40}} = 0,16\,mol\\
{n_{HCl}} = 0,15 \times 2 + 0,16 \times 2 = 0,62\,mol\\
{C_M}HCl = \dfrac{{0,62}}{{0,2}} = 3,1M\\
e)\\
{n_{MgC{l_2}}} = 0,15 + 0,16 = 0,31\,mol\\
{m_{MgC{l_2}}} = 0,31 \times 95 = 29,45g\\
g)\\
{C_M}MgC{l_2} = \dfrac{{0,31}}{{0,2}} = 1,55M
\end{array}\)