`a)(2x+1).(3x-5)-(2x-1)^2-2x^2+10`

`=6x^2-10x+3x-5-(4x^2−4x+1)-2x^2+10`

`=6x^2-10x+3x-5-4x^2+4x-1-2x^2+10`

`=-3x+4.`

`b)4.(2x+3).(2x-3)-(4x+3)^2+2x+1`

`=4.(4x^2-9)-(16x^2+24x+9)+2x+1`

`=16x^2-36-16x^2-24x-9+2x+1`
`=-22x-44.`

`c)(3x+4)^2-(3x+2).(4x-5)+3x^2+11`

`=9x^2+24x+16-(12x^2-15x+8x-10)+3x^2+11`
`=9x^2+24x+16-12x^2+15x-8x+10+3x^2+11`
`=31x+37.`

`d)(2x+1)^3-(x+2).(3x+2)^2+x^3+8 `

`=8x^3+12x^2+6x+1-(x+2)(9x^2+12x+4)+x^3+8 `
`=8x^3+12x^2+6x+1-(9x^3+12x^2+4x+18x^2+24x+8)+x^3+8 `
`=8x^3+12x^2+6x+1-9x^3-12x^2-4x-18x^2-24x-8+x^3+8 `
`=−18x^2−22x+1.`

a, (2x+1) (3x-5) - (2x-1)²- 2x² + 10

= 6x² - 10x + 3x - 5 - (4x²- 4x + 1) - 2x²+ 10 

= 6x² - 10x + 3x - 5 - 4x²+ 4x - 1 - 2x²+ 10

=  -3x +4

b, 4 (2x+3) (2x-3) - (4x+3)²+ 2x + 1

= 4 (4x²- 9) - (4x+3)²+ 2x + 1

= 16x² - 36 - (16x² + 24x + 9) + 2x + 1

= 16x² - 36 - 16x² - 24x - 9 + 2x + 1

= -22x - 44

c, (3x+4)²- (3x+2) (4x-5)+3x² + 11

= 9x² + 24 +16 - (12x²- 15x + 8x - 10)+3x²+ 11

= 9x²+ 24x + 16 − 12x²+ 15x − 8x + 10 + 3x²+ 11

= 31x+37

d, (2x+1)³- (x+2) (3x+2)²+ x³+ 8

= 8x³+ 12x²+ 6x +1- (x+2) (9x²+ 12x +4)+ x³+ 8

= 8x³+ 12x²+ 6x +1− (9x³+ 12x²+ 4x + 18x²+ 24x +8)+x³+ 8

= 8x³+ 12x²+ 6x +1 − 9x³− 12x²− 4x − 18x²− 24x − 8 + x³+ 8

= −18x²− 22x + 1

  - Chúc bn học tốt.