Đáp án:

\begin{array}{|c|c|c|}\hline \text{Oxit}&\text{Phân loại}&\text{Tên gọi}&\text{Axit hoặc bazo tương ứng}\\\hline \text{$N_2O_5$}&\text{Oxit axit}&\text{Đinito pentaoxit}&\text{$HNO_3$}\\\hline \text{FeO}&\text{Oxit bazo}&\text{Sắt (II) oxit}&\text{$Fe(OH)_2$}\\\hline \text{$SO_2$}&\text{Oxit axit}&\text{Lưu huỳnh đioxit}&\text{$H_2SO_3$}\\\hline \text{MgO}&\text{Oxit bazo}&\text{Magie oxit}&\text{$Mg(OH)_2$}\\\hline \text{BaO}&\text{Oxit bazo}&\text{Bari oxit}&\text{$Ba(OH)_2$}\\\hline \text{CuO}&\text{Oxit bazo}&\text{Đồng (II) oxit}&\text{$Cu(OH)_2$}\\\hline \text{$CO_2$}&\text{Oxit axit}&\text{Cacbon đioxit}&\text{$H_2CO_3$}\\\hline \text{$P_2O_5$}&\text{Oxit axit}&\text{Điphotpho pentaoxit}&\text{$H_3PO_4$}\\\hline \text{MnO}&\text{Oxit bazo}&\text{Mangan oxit}&\text{$Mn(OH)_2$}\\\hline \text{$SO_3$}&\text{Oxit axit}&\text{Lưu huỳnh trioxit}&\text{$H_2SO_4$}\\\hline \end{array}

`#begiaphuong`

Đáp án:

`↓`

Giải thích các bước giải:

\begin{array}{|c|c|c|}\hline \text{Oxit}&\text{Phân loại}&\text{Tên gọi}&\text{Axit hoặc bazo tương ứng}\\\hline \text{$N_2O_5$}&\text{Oxit axit}&\text{Đinito pentaoxit}&\text{$HNO_3$}\\\hline \text{FeO}&\text{Oxit bazo}&\text{Sắt (II) oxit}&\text{$Fe(OH)_2$}\\\hline \text{$SO_2$}&\text{Oxit axit}&\text{Lưu huỳnh đioxit}&\text{$H_2SO_3$}\\\hline \text{MgO}&\text{Oxit bazo}&\text{Magie oxit}&\text{$Mg(OH)_2$}\\\hline \text{BaO}&\text{Oxit bazo}&\text{Bari oxit}&\text{$Ba(OH)_2$}\\\hline \text{CuO}&\text{Oxit bazo}&\text{Đồng (II) oxit}&\text{$Cu(OH)_2$}\\\hline \text{$CO_2$}&\text{Oxit axit}&\text{Cacbon đioxit}&\text{$H_2CO_3$}\\\hline \text{$P_2O_5$}&\text{Oxit axit}&\text{Điphotpho pentaoxit}&\text{$H_3PO_4$}\\\hline \text{MnO}&\text{Oxit bazo}&\text{Mangan oxit}&\text{$Mn(OH)_2$}\\\hline \text{$SO_3$}&\text{Oxit axit}&\text{Lưu huỳnh trioxit}&\text{$H_2SO_4$}\\\hline \end{array}