Đáp án:

`↓`

Giải thích các bước giải:

`a)` 

- `C``+``O_2` $\xrightarrow[]{t^o}$ `CO_2↑`

- `CO_2``+``CaO``→``CaCO_3↓`

- `CaCO_3``+``2HCl``→``CaCl_2``+``CO_2↑``+``H_2O`

- `CaCl_2``+``2AgOH``→``Ca(OH)_2``+``2AgCl↓`

- `Ca(OH)_2``+``CO_2``→``CaCO_3``+``H_2O`

- `CaCO_3` $\xrightarrow[]{t^o}$ `CaO``+``CO_2↑`

- `CaO``+``H_2SO_4``→``CaSO_4``+``H_2O`

`b)`

- `2Mg``+``O_2` $\xrightarrow[]{t^o}$ `2MgO`

- `MgO``+``2HCl``→``MgCl_2``+``H_2O`

- `MgCl_2``+``2NaOH``→``Mg(OH)_2↓``+``2NaCl`

- `Mg(OH)_2` $\xrightarrow[]{t^o}$ `MgO``+``H_2O`

- `MgO``+``H_2SO_4``→``MgSO_4``+``H_2O`

- `MgSO_4``+``BaCl_2``→``BaSO_4↓``+``MgCl_2`

`c)`

- `2Fe``+``3Cl_2` $\xrightarrow[]{t^o}$ `2FeCl_3`

- `Cl_2``+``2NaOH` $\xrightarrow[cmn]{đpdd}$ `NaClO``+``NaCl``+``H_2O`

- `Cl_2``+``H_2O` $\rightleftharpoons$ `HClO``+``HCl`

- `Cl_2``+``H_2` $\xrightarrow[]{t^o}$ `2HCl`

`#nam`

 `a)`

`C + O_2` $\xrightarrow{t^o}$ `CO_2`

`CaO + CO_2 -> CaCO_3`

`CaCO_3 + HCl -> CaCl_2 + CO_2↑ + H_2O`

`2H_2O+CaCl_2`$\xrightarrow[cmn]{đpdd}$ `Ca(OH)_2+Cl_2+2H_2`

`Ca(OH)_2 + Na_2CO_3 -> CaCO_3↓ + 2NaOH`

`CaCO_3` `$\xrightarrow{t^o}$ `CaO + H_2O`

`CaO + SO_3 -> CaSO_4`

`b)`

`2Mg + O_2` $\xrightarrow{t^o}$ `MgO`

`MgO +2HCl -> MgCl_2 + H_2`

`MgCl_2 + NaOH -> Mg(OH)_2↓ + 2NaCl`

`Mg(OH)_2` $\xrightarrow{t^o}$ `MgO + H_2O`

`MgO + SO_3 -> MgSO_4`

`MgSO_4 + BaCl_2 -> BaSO_4↓+MgCl_2`

`c)`

`2Fe + 3Cl_2` $\xrightarrow{t^o}$ `2FeCl_3`

`Cl_2 + H_2` $\xrightarrow{as}$ `2HCl`

`Cl_2 + H_2O -> HCl + HClO`

`Cl_2 + 2NaOH → NaCl + NaClO + H_2O`