Trắc nghiệm Toán 6 Bài 9 Phép trừ phân số

A. \( - \frac{{17}}{9}\)

B. \(\frac{{ - 17}}{9}\)

C. \(\frac{{17}}{{ - 9}}\)

D. Cả ba đáp án A, B, C đều đúng 

A. \(\frac{{ - 2}}{3},\frac{3}{2}\)

B. \(\frac{{ - 12}}{{13}},\frac{{13}}{{ - 12}}\)

C. \(\frac{1}{2}, - \frac{1}{2}\)

D. \(\frac{3}{4}, - \frac{4}{3}\)

A. \(\frac{1}{{10}}\)

B. \(\frac{2}{{10}}\)

C. \(\frac{1}{{5}}\)

D.  - \(\frac{1}{{10}}\)

A. \({ - \frac{{27}}{{11}}}\)

B. \({ - \frac{{11}}{{27}}}\)

C. \({ \frac{{27}}{{11}}}\)

D. \( - \left( { - \frac{{27}}{{11}}} \right)\)

A. \(\frac{9}{{14}}\)

B. \(\frac{1}{{14}}\)

C. \(\frac{11}{{14}}\)

D. \(\frac{7}{{14}}\)

A. \(\frac{5}{{18}}\)

B. \(\frac{5}{{36}}\)

C. -\(\frac{11}{{18}}\)

D. \(\frac{5}{{6}}\)

A. \( - \frac{{5}}{{16}}\)

B. \[\frac{{5}}{{16}}\]

C. \[\frac{{19}}{{16}}\]

D. \[\frac{{-19}}{{16}}\]

A. 2

B. 1

C. -1

D. 5

A. \(\frac{4}{{16}} - \frac{1}{2} = \frac{5}{{26}}\)

B. \(\frac{1}{{2}} - \frac{1}{3} = \frac{5}{{6}}\)

C. \(\frac{17}{{20}} - \frac{1}{5} = \frac{13}{{20}}\)

D. \(\frac{4}{{16}} + \frac{1}{2} = \frac{5}{{26}}\)

A. \(\frac{1}{3}\)

B. \(\frac{-1}{3}\)

C. \(\frac{11}{3}\)

D. \(\frac{-11}{3}\)

A. \( - \frac{21}{4}\)

B. \(  \frac{3}{16}\)

C. \( - \frac{1}{4}\)

D. \(  \frac{1}{4}\)

A. \( \frac{{16}}{{21}}\)

B. \( \frac{{32}}{{21}}\)

C. \( - \frac{{16}}{{27}}\)

D. \( - \frac{{16}}{{21}}\)

A. \(\frac{8}{9}\)

B. \(\frac{1}{9}\)

C. - \(\frac{1}{9}\)

D. \(\frac{15}{9}\)

A. \(\frac{3}{{2}}\)

B. \(\frac{-3}{{2}}\)

C. \(\frac{5}{{12}}\)

D. \(\frac{-5}{{12}}\)

A. \( - \frac{1}{2}\)

B. \( \frac{1}{2}\)

C. \( - \frac{3}{2}\)

D. \( \frac{3}{2}\)

A. \(\frac{{199}}{{1000}}\)

B. \(\frac{{699}}{{1000}}\)

C. \(\frac{{499}}{{1000}}\)

D. \(\frac{{999}}{{1000}}\)