Quy tắc đường chéo:

$\rm {M_{SO_2}=64}\hspace{4cm}{16}\\\hspace{1,4cm}\huge{\searrow}\hspace{2,5cm}\huge{\nearrow}\\\hspace{2,7cm}{M_X = 48}\\\hspace{1,4cm}\huge{\nearrow}\hspace{2,5cm}\huge{\searrow}\\{M_{O_2} = 32}\hspace{4cm}{16}$

$\rm \dfrac{n_{SO_2}}{n_{O_2}} = \dfrac{16}{16} = 1$

$\rm \to n_{SO_2} =n_{O_2}$

Phần trăm thể tích mỗi khí:

$\rm \%V_{SO_2} = \dfrac{n_{SO_2}}{n_{SO_2} + n_{O_2}} \times 100\% = 50\%$

$\rm \%V_{O_2} = 100\% - 50\% = 50\%$

Phần trăm khối lượng mỗi khí:

$\rm \%m_{SO_2} = \dfrac{64n_{SO_2}}{64n_{SO_2} + 32n_{O_2}} \times 100\% \approx 66,667\%$

$\rm \%m_{O_2} = 100\% - 66,667\% = 33,333\%$

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