Đáp án:

Thí nghiệm 1:

$H_2+I_2\rightleftharpoons 2HI$

$K_C=\dfrac{[HI]^2}{[H_2][I_2]}=\dfrac{n_{HI(CB)}^2 }{n_{H_2(CB)}.n_{I_2(CB)} }$

$K_C=\dfrac{1,6^2}{0,2.0,2}=64$

Thí nghiệm 2:

$2HI\rightleftharpoons H_2+I_2$ 

$K_C=\dfrac{[H_2][I_2] }{[HI]^2}=\dfrac{n_{H_2(CB)}.n_{I_2(CB)} }{n_{HI(CB)}^2}$ 

$K_C=\dfrac{0,2.0,2}{1,6^2}=\dfrac{1}{64}$