`n_{N_2\ bd}={4,48}/{22,4}=0,2(mol)`

`->C_{N_2\ bd}={0,2}/{10}=0,02M`

`n_{H_2\ bd}={17,92}/{22,4}=0,8(mol)`

`->C_{H_2\ bd}={0,8}/{10}=0,08M`

`N_2+3H_2`  $\buildrel{{t^o,p,Fe}}\over\rightleftharpoons$  `2NH_3`

Do `0,02<{0,08}/3->H` theo `N_2.`

`->C_{N_2\ pu}=0,02.25\%=0,005M`

`->C_{H_2\ pu}=0,015M;[NH_3]=0,01M`

`->[H_2]=0,08-0,015=0,065M;[N_2]=0,02-0,005=0,015M`

`->K_C={[NH_3]^2}/{[N_2][H_2]^3}={0,01^2}/{0,015.0,065^3}\approx 24,28`