Đáp án+Giải thích các bước giải:

Câu 7 

`a.`

`Na_{2}O+H_{2}O→2NaOH`

`n_{H_{2}O}=n_{Na_{2}O}=(12,4)/(62)=0,2(mol)`

`→m_{H_{2}O}=0,2.18=3,6(g)`

`b.`

`CaO+H_{2}O→Ca(OH)_{2}`

`n_{H_{2}O}=n_{CaO}=(5,6)/(56)=0,1(mol)`

`→m_{H_{2}O}=0,1.18=1,8(g)`

Câu 8

`HNO_{3}` : acid nitric

`BaCO_{3}` : barium cacbonat

`Na_{2}SO_{4}` : sodium sulfat 

`NaHCO_{3}` : Sodium hydrogen carbonate

`Cu(OH)_{2}` : copper hidroxide

`Fe_{2}O_{3}` : iron(III) oxide 

`P_{2}O_{5}` : diphosphor pentoxide 

`HCl` : hydrochloric acid

`Fe(OH)_{3}` : iron(III) hydroxide

`NaOH` : sodium hydroxide

`7)`

`a)`

`n_{Na_2}={12,4}/{62}=0,2(mol)`

`Na_2O+H_2O->2NaOH`

`0,2->0,2(mol)`

`m_{H_2O}=0,2.18=3,6(g)`

`b)`

`n_{CaO}={5,6}/{56}=0,1(mol)`

`CaO+H_2O->Ca(OH)_2`

`0,1->0,1(mol)`

`m_{H_2O}=0,1.18=1,8(g)`

`8)`

`HNO_3:` nitric acid

`BaCO_3:` barium carbonate

`Na_2SO_4:` sodium sulfate

`NaHCO_3:` sodium hydrogen carbonate

`Cu(OH)_2:` cupric hydroxide

`Fe_2O_3:` ferric oxide

`P_2O_5:` diphosphorus pentoxide

`HCl:` hydrochloric acid

`Fe(OH)_3:` ferric hydroxide

`NaOH:` sodium hydroxide