`a)`

`n_{Zn}=\frac{6,5}{65}=0,1(mol)`

`Zn+2HCl→ZnCl_{2}+H_{2}`

`0,1`        `0,2`       `0,1`               `0,1`    / `mol`

`⇒V_{H_{2}}=0,1.24,79=2,479` ( lít )

`b)C_{M_{ddHCl}}=\frac{0,2}{0,2}=1(M)`

`c)n_{ZnCl_{2}}=\frac{6}{136}=\frac{3}{68}(mol)`

`⇒H_{%}=\frac{\frac{3}{68}}{0,1}.100%=44,12%`

`n_{Zn}={6,5}/65=0,1(mol)`

`PTHH:Zn+2HCl->ZnCl_2+H_2`

`a.n_{H_2}=n_{Zn}=0,1(mol)`

`V_{H_2}=n.24,79=0,1.24,79=2,479(l)`

`b.n_{HCl}=2n_{Zn}=0,1.2=0,2(mol)`

`200ml=0,2l`

`C_M HCl =n/V ={0,2}/{0,2}=1(M)`

`c.n_{ZnCl_2(l t)}=n_{Zn}=0,1(mol)`

`m_{ZnCl_2(l t)}=0,1.136=13,6(g)`

`=>H=6/{13,6}.100%~~44,12%`