Đáp án: $A$

$n_{C_8H_{18}}:n_{C_7H_{16}}=a:b$

`->`$\dfrac{114a+100b}{a+b}=28.22 \times 4$

`=>`$\dfrac{a}{b}=\dfrac{23x}{2x}$

`=>`$V_{xăng}=(23x+2x) \times 22.4=25x \times 22.4(L)$

Bảo toàn $e:$

$(8 \times 4+18) \times 23x+(7 \times 4+16) \times 2x=4n_{O_2}$

`=>`$n_{O_2}=309.5x(mol)$

`=>`$V_{kk}=306.5x \times \dfrac{100}{21} \times 22.4 =\dfrac{30950x}{21} \times 22.4(L)$

`=>`$\dfrac{V_{xăng}}{V_{kk}}=\dfrac{25x \times 22.4}{\dfrac{30950x}{21} \times 22.4}=\dfrac{21}{1238}$

Có:  $\dfrac{1}{V}=\dfrac{21}{1238}$

`=>`$V=\dfrac{1238}{21}≈59(L)$