` a) `

` Zn+2HCl -> ZnCl_2 + H_2 `

` n_(Zn) = m/M = (13)/(65) = 0,2``(mol)`

` -> m_(HCl) = n.M = (0,2.2) . 36,5 = 7,3``(g) ` 

` b) `

` m_(ZnCl_2) =n.M = 0,2 . 136 = 27,2``(g) ` 

` c) `

` V_(H_2) = n . 24,79 = 0,2 . 24,79 = 4,948``(l) ` 

$\rm n_{Zn} = \dfrac{13}{65} = 0,2$ mol

Phản ứng xảy ra:

$\rm Zn + 2HCl \to ZnCl_2 + H_2$

a)Theo PTHH:

$\rm n_{HCl} = 2n_{Zn} = 2 \times 0,2 = 0,4$ mol

$\rm \to m_{HCl} = 0,4 \times 36,5 = 14,6g$

b)Theo PTHH

$\rm n_{ZnCl_2} = n_{Zn} = 0,2$ mol

$\rm \to m_{ZnCl_2} = 0,2 \times 136 = 27,2g$

c)Theo PTHH

$\rm n_{H_2} = n_{Zn} = 0,2$ mol

$\rm \to V_{H_2} = 0,2 \times 24,79 = 4,958L$