tóm tắt:

`V_{X(CH_4,C_2H_2)}:8(l) + 0,2ml Br_2` `2,5M`

`%VCH_4=?;%VC_2H_2=?`

`n_{Br_2}=0,2.2,5=0,5(mol)`

`PTHH:C_2H_2+2Br_2->C_2H_2Br_4`

`(mol)`      `0,25`       `←0,5→`        `0,25`

`V_{C_2H_2}=0,25.22,4=5,6(l)`

`=>%V_{C_2H_2}={5,6}/8 .100%=70%`

`=>%V_{CH_4}=30%`

Tóm tắt:

`X:CH_4,C_2H_2+200mL\ Br_2\ 2,5M`

`\%V_{CH_4}=?;\%V_{C_2H_2}=?`

`C_2H_2+2Br_2->C_2H_2Br_4`

`n_{Br_2}=0,2.2,5=0,5(mol)`

`->n_{C_2H_2}=1/2n_{Br_2}=0,25(mol)`

`\%V_{C_2H_2}={0,25.22,4}/{8}.100\%=70\%`

`\%V_{CH_4}=100-70=30\%`