`\color{blue}{#aether}`

`n_{C_2H_4}=(4,48)/(22,4)=0,2` `mol`

PTHH : `C_2H_4+Br_2->C_2H_4Br_2`

Mol :      `0,2`     `->0,2`

`=>a=(0,2)/(0,05)=4` `M`

`n_{C_2H_2}=(4,48)/(22,4)=0,2` `mol`

PTHH : `C_2H_2+2Br_2->C_2H_2Br_4`

Mol :         `0,2`   `->0,4` 

`=>V_{Br_2}=(0,4)/(4)=0,1` `l``=100` `ml`

`n_{C_2H_4}={4,48}/{22,4}=0,2(mol)`

`PTHH:C_2H_4+Br_2->C_2H_4Br_2`

`n_{Br_2}=n_{C_2H_4}=0,2(mol)`

`50ml=0,05l`

`=>a=C_M Br_2={0,2}/{0,05}=4(M)`

`n_{C_2H_2}={4,48}/{22,4}=0,2(mol)`

`PTHH:C_2H_2+2Br_2->C_2H_2Br_4`

`n_{Br_2}=2n_{C_2H_2}=0,4(mol)`

`=>V_{Br_2}={0,4}/4=0,1(l)=100(ml)`