$a) CH_3CH_2CH_3+Cl_2\xrightarrow{as}CH_3CHClCH_3+HCl$

$b)C_2H_4+H_2\xrightarrow{Ni,t^o}C_2H_6$

$c) nCH_2=CH_2\xrightarrow{t^o,p,xt}(\kern-6pt- CH_2-CH_2 -\kern-6pt)_n$
$d) C_2H_2+H_2O\xrightarrow{80^oC,HgSO_4/H_2SO_4}CH_3CHO$

$e) C_2H_5OH\xrightarrow{H_2SO_4 đ,170^oC}C_2H_4+H_2O$

$CaC_2+2HCl\rightarrow CaCl_2+C_2H_2$

$f) C_2H_2+2Br_2\rightarrow C_2H_2Br_4$

$C_2H_4+Br_2\rightarrow C_2H_4Br_2$

$g) 3C_2H_4+2KMnO_4+4H_2O\rightarrow 3C_2H_4(OH)_2+2MnO_2+2KOH$

$3C_2H_2+8KMnO_4\rightarrow 3(COOK)_2+8MnO_2+2H_2O+2KOH$

Đáp án:

a, 

$CH_3-CH_2-CH_3+Cl_2\xrightarrow{{as, 1:1}} \left[ \begin{array}{l} CH_3-CHCl-CH_3\\ CH_3-CH_2-CH_2Cl\end{array} \right.+HCl$

b,

$CH_2=CH_2+H_2\xrightarrow{{Ni, t^o}} CH_3-CH_3$ 

c,

$nCH_2=CH_2 \xrightarrow{{t^o, p, xt}} (\kern-6pt-CH_2-CH_2-\kern-6pt)_n$ 

d,

$CH\equiv CH+H_2O\xrightarrow{{80^oC, HgSO_4, H_2SO_4}} CH_3CHO$ 

e,

$C_2H_5OH\xrightarrow{{H_2SO_4 đ, 180^oC}} C_2H_4+H_2O$

$CaC_2+2H_2O\to Ca(OH)_2+C_2H_2$

f,

$C_2H_4+Br_2\to CH_2Br-CH_2Br$ 

$C_2H_2+2Br_2\to CHBr_2-CHBr_2$ 

g,

$3C_2H_4+2KMnO_4+4H_2O\to 3 CH_2OH-CH_2OH+2MnO_2+2KOH$ 

$3C_2H_2+8KMnO_4\to 3(COOK)_2+8MnO_2+2KOH+2H_2O$