`a)`

`FeO+2HCl->FeCl_2+H_2O`

`Al_2O_3+6HCl->2AlCl_3+3H_2O`

`FeCl_2+2NaOH->Fe(OH)_2+2NaCl`

`AlCl_3+3NaOH->Al(OH)_3+3NaCl`

`Al(OH)_3+NaOH->NaAlO_2+2H_2O`

`4Fe(OH)_2+O_2`  $\xrightarrow{t^o}$  `2Fe_2O_3+4H_2O`

`b)`

`n_{Fe_2O_3}={16}/{160}=0,1(mol)`

Theo PT: `n_{FeO}=2n_{Fe_2O_3}=0,2(mol)`

`->m_{FeO}=0,2.72=14,4(g)`

`->m_{Al_2O_3}=24,6-14,4=10,2(g)`

`c)`

`n_{Al_2O_3}={10,2}/{102}=0,1(mol)`

Theo PT:

`\sum n_{HCl}=2n_{FeO}+6n_{Al_2O_3}=1(mol)`

`n_{FeCl_2}=n_{FeO}=0,2(mol)`

`n_{AlCl_3}=2n_{Al_2O_3}=0,2(mol)`

`->m_{dd\ HCl}={1.36,5}/{14,6\%}=250(g)`

`->m_{dd\ spu}=24,6+250=274,6(g)`

`->C\%_{FeCl_2}={0,2.127}/{274,6}.100\%\approx 9,25\%`

         `C\%_{AlCl_3}={0,2.133,5}/{274,6}.100\%\approx 9,72\%`