C1

`C_2H_4 + H_2O overset[t^@, H_2SO_4][->] C_2H_5OH`

`C_2H_5OH+O_2 overset[text[mengiam]][->] CH_3COOH+H_2O`

`C_2H_5OH+CH_3COOH` $\buildrel{{H_2SO_4 \text{dac}, t^\circ}}\over\rightleftharpoons$ `CH_3COOC_2H_5+H_2O`

C2

`2Na+2C_2H_5OH -> 2C_2H_5ONa+H_2`

`n_[Na]=[2.3]/23=0.1` (mol)

PT : `n_[H_2]=1/2n_[Na]=1/2 * 0.1=0.05` (mol)

`-> V=0.05 * 22.4=1.12` (lit)

$C_2H_4 +H_2O \xrightarrow{H_2SO_4(đ) ,to}C_2H_5OH$ 

$C_2H_5OH + O_2 \xrightarrow{enzim} CH_3COOH +H_2O$ 

$C_2H_5OH +CH_3COOH \buildrel{{H_2SO_4(đ),to}}\over\rightleftharpoons CH_3COOC_2H_5 +H_2O$ 

Câu `2` 

$\rm PTHH: Na +C_2H_5OH \xrightarrow{} C_2H_5ONa +\dfrac{1}{2} H_2$ 

`n_{Na}=\frac{2,3}{23}=0,1(mol)`

theo pthh 

`n_{H_2}=\frac{1}{2}n_{Na}=0,05(mol)`

`->V_{H_2}=0,05.22,4=1,12(l)`