Đáp án:

$\rm C_2H_5OH+O_2\xrightarrow{men,\ t^°}CH_3COOH+H_2O\\CH_3COOH+C_2H_5OH\overset{H_2SO_4\ (conc.),\ t^°}\leftrightarrows CH_3COOC_2H_5+H_2O\\CH_3COOC_2H_5+NaOH\xrightarrow{t^°}CH_3COONa+C_2H_5OH\\C_2H_5OH+Na\to C_2H_5ONa+\dfrac{1}{2}H_2$

Đáp án:

Giải thích các bước giải:

`C_2H_5OH overset(1) (->) CH_3COOH overset(2) (->) CH_3COOC_2H_4 overset(3) (->) CH_3COONa ` $\\$

          $\downarrow$`(4)`

`C_2H_5ONa`

`(1)C_2H_5OH + O_2 overset(enzim) (->)CH_3COOH + H_2O` 

 `(2)C_2H_5OH + CH_3COOH ` $\buildrel{{t^o,xt}}\over\rightleftharpoons$ `CH_3COOC_2H_5 + H_2O`

`(4)` `C_2H_5OH + Na -> C_2H_5Na + 1/2H_2`

`(3)CH_3COOC_2H_5 + NaOH -> CH_3COONa + C_2H_5OH `