Đáp án:

(1) $CH_3Cl+NaOH\xrightarrow{{t^o}} CH_3OH+NaCl$ 

(2) $CH_3OH+CuO\xrightarrow{{t^o}} HCHO+Cu+H_2O$ 

(3) $2HCHO+O_2\xrightarrow{{Mn^{2+}, t^o}} 2HCOOH$ 

(4) $HCOOH+C_2H_5OH \buildrel{{H_2SO_4 đ, t^o}}\over\rightleftharpoons HCOOC_2H_5+H_2O$ 

(5) $CH_3OH+CO\xrightarrow{{t^o, xt}} CH_3COOH$ 

(6) $CH_3COOH+NaOH\to CH_3COONa+H_2O$ 

(7) $CH_3COONa+NaOH\xrightarrow{{CaO, t^o}} CH_4+Na_2CO_3$

`1)`

`CH_3Cl+ NaOH`$\xrightarrow{t°}$`CH_3OH+ NaCl`

`2)`

`CH_3OH + CuO`$\xrightarrow{t°}$`HCHO + Cu + H_2O`

`3)`

`HCHO + Br_2+ H_2O→ HCOOH + 2HBr` 

`4)`

`HCOOH + C_2H_5OH`$\buildrel{{H_2SO_4(đ),t°}}\over\rightleftharpoons$`HCOOC_2H_5+ H_2O`

`5)`

`CH_3OH + CO`$\xrightarrow{t°,xt}$`CH_3COOH` 

`6)`

`CH_3COOH + Na→ CH_3COONa+1/2H_2`

`7)`

`CH_3COONa + NaOH `$\xrightarrow{CaO,t°}$`CH_4+Na_2CO_3`