n=int(input())
a=list(map(int,input().split()))
d,s=0,0
b=[]
for i in a:
    if 30<i<50:
        print(i,end=' ')
    if i%5==0:
        d+=1
        s+=i
    if i>0 and i%2==0:
        b.append(i)
print()
print(d,s)
print(*b)

c++ nha

#include <bits/stdc++.h>
#define ll long long
using namespace std;
int main()
{
    ll n;
    cin>>n;
    ll a[n],tong=0,dem=0;
    map<ll,ll> b;
    for(ll i=0;i<n;i++)
    {
        cin>>a[i];
        if(a[i]>30&&a[i]<50) tong+=a[i];
        if(a[i]%5==0) dem++;
        if(a[i]%2==0&&a[i]>0)
        {
            b.insert(make_pair(i,a[i]));
        }
    }
    cout<<"tong cac so lon hon 30 va nho hon 50 la: "<<tong<<endl;
    cout<<"so luong cac so chia het cho 5 la: "<<dem<<endl;
    cout<<"danh sach b: ";
    for(pair<ll,ll> i:b)
    {
        cout<<i.second<<" ";
    }
}