Đáp án:

Giải thích các bước giải:

2)

\(\begin{array}{l}
a)\\
{C_2}{H_4} + B{r_2} \to {C_2}{H_4}B{r_2}\\
n{C_2}{H_4}B{r_2} = \frac{{37,62}}{{188}} = 0,2\,mol\\
 =  > nB{r_2} = 0,2\,mol\\
CMB{r_2} = \frac{{0,2}}{{0,2}} = 1M\\
b)\\
n{C_2}{H_4} = 0,2\,mol\\
\% V{C_2}{H_4} = \frac{{0,2 \times 22,4}}{{17,92}} \times 100\%  = 25\% \\
\% VC{H_4} = 100 - 75 = 25\% 
\end{array}\)

3)

\(\begin{array}{l}
a)\\
{C_2}{H_4} + B{r_2} \to {C_2}{H_4}B{r_2}\\
nC{H_4} = \frac{{3,36}}{{22,4}} = 0,15\,mol\\
nhh = \frac{{5,6}}{{22,4}} = 0,25\,mol\\
 =  > n{C_2}{H_4} = 0,25 - 0,15 = 0,1mol\\
 =  > nB{r_2} = 0,1\,mol\\
CMB{r_2} = \frac{{0,1}}{{0,2}} = 0,5M\\
b)\\
\% V{C_2}{H_4} = \frac{{0,1 \times 22,4}}{{5,6}} \times 100\%  = 40\% \\
\% VC{H_4} = 100 - 40 = 60\% 
\end{array}\)